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Ne4ueva [31]
4 years ago
14

What is the range of values for measurements 300 +2%

Mathematics
1 answer:
leonid [27]4 years ago
3 0
300*2/100. = 3*2=6

300+6 =306


Done!
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Element X is a radioactive isotope such that every 90 years, its mass decreases by half. Given that the initial mass of a sample
steposvetlana [31]

Answer:

approximately 27 grams

Work Shown:

Half life formula

y = A*(0.5)^(x/H)

where,

A = starting amount = 30 grams

H = half life period = 90 years

x = number of years that pass by = 12

y = amount left over after x years

Let's plug the values for x, A and H into the formula to find y

y = A*(0.5)^(x/H)

y = 30*(0.5)^(12/90)

y = 27.3516746567466

y = 27 .... rounding to the nearest whole number

4 0
3 years ago
The distance from Earth to the moon is about 4*10 fifth power kilometers. The distance from Earth to Mars is about 5*10 the seve
uysha [10]

Answer: distance from earth to moon is 4x10^5= 4,000,000

The distance from Earth to Mars is about 5x10^7= 50,000,000.

Step-by-step explanation:

8 0
3 years ago
2m^2n^4/6m^5n^3 assume no variable equals zero.
Andrews [41]
<span>2m^2n^4/6m^5n^3
           n
 =   --------
         3m^3</span>
8 0
3 years ago
What digit is in the hundredths place 132.054 ​
Anit [1.1K]

Answer:

5

Step-by-step explanation:

0 is 10ths 5 is 100ths

4 0
4 years ago
Read 2 more answers
S the expression x3•x3•x3 equivalent to x3•3•3
Artyom0805 [142]
Remember
(x^m)(x^n)=x^(m+n)
and difference of 2 perfect squres
(a²-b²)=(a-b)(a+b)
and sum or difference of 2 perfect cubes

so
(x^3)(x^3)(x^3)=x^(3+3+3)=x^9
so

x^9=3*3*x^3
x^9=9x^3
minus 9x^3 both sides
0=x^9-9x^3
factor
0=(x^3)(x^6-9)
factor difference of 2 perfect squraes
0=(x^3)(x^3-3)(x^3+3)
factor differnce or sum of 2 perfect cubes (force 3 into (∛3)³)
0=(x³)(x-∛3)(x²+x∛3+∛9)(x+∛3)(x²-x∛3+∛9)
set each to zero

x³=0
x=0

x-∛3=0
x=∛3

x²+x∛3+∛9=0 has no solution

x+∛3=0
x=-∛3

x²-x∛3+∛9=0 has no solution



so the solutions are
x=-∛3, 0, ∛3
3 0
4 years ago
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