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Delvig [45]
3 years ago
7

HELP ME PLEASE HELP PLEASE HELP

Mathematics
1 answer:
Marina86 [1]3 years ago
5 0

Answer:

c=\sqrt{12} or c=3.46410161514

Step-by-step explanation:

Use Pythagoras theorem: a²=b²+c², where a is the side opposite the right angle, and b and c are the other sides:

a²=b²+c²

4²=2²+c²

16=4+c²

c²=12

c=\sqrt{12} or c=3.46410161514

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To get to school, Grayson usually walks 1.5 miles west and 0.8 miles north on the sidewalks. Because he is in a hurry, he has de
Alex17521 [72]

Answer:

Grayson has to walk 1.7 miles across the field.

Step-by-step explanation:

We have drawn the diagram for your reference.

Given:

Grayson usually walks 1.5 miles west on the side walks

According to Diagram we can say;

CA = 1.5 miles

Also Given:

Grayson also walks 0.8 miles north on the sidewalks

So According to Diagram we can say;

BA =0.8 miles

Now we need to find number of miles Grayson have to walk across the field.

According to diagram we can say;

We have to find CA.

Assuming the diagram  to be right angled triangle.

We can find CA using Pythagoras theorem.

{CA}^2 = {CB}^2+{BA}^2

Substituting the given values we get;

{CA}^2 =1.5^2+0.8^2 = 2.25 +0.64 =2.89

Taking square root on both side we get;

\sqrt{{CA}^2} = \sqrt{2.89} \\\\CA = 1.7 \ mi

Hence Grayson has to walk 1.7 miles across the field.

4 0
3 years ago
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