Ask question

Ask question

All categories

3 years ago

14

Please help me with this maths question

1 answer:

Keith_Richards [23]3 years ago

8 0

Answer:

add all of them together then divide bye the number of lines

Step-by-step explanation:

You might be interested in

What is the equation of the line perpendicular to y=2x+3.14 going through the points (2,4)?

inessss [21]

Answer:

$x+2y-10=0$

Step-by-step explanation:

Consider an equation: $y=mx+c$

Here, m is the slope of the line and c is the y-intercept.

Given equation is $y=2x+3.14$

Here, slope is $m=2$

As product of slopes of two perpendicular lines is equal to $-1$ , slope of the required line is $m_1=\frac{-1}{m}=\frac{-1}{2}$ .

Let $(x_1,y_1)=(2,4)$

Equation of the required line is $y-y_1=m_1(x-x_1)$

$y-4=\frac{-1}{2}(x-2)\\2(y-4)=-1(x-2)\\2y-8=-x+2\\x+2y-8-2=0\\x+2y-10=0$

8 0

3 years ago

The point A(4,3) is reflected over the point (3,5) and its image is point B. What

mamaluj [8]

B(5,1) I’m smart and don’t worry the answer is correct

5 0

3 years ago

Is anyone able to give a step by step process to this?

Thepotemich [5.8K]

Answer:

The value of y is 3 cm.

Step-by-step explanation:

Given,

Perimeter of triangle = $29\ cm$

Solution,

Lets redraw the triangle with nomenclature ABC, given in the attachment.

∴P(ΔABC) = 29 cm (P stands for perimeter)

Length of AB = $y+9$

Length of BC = $2y$

Length of CA = $4y-1$

Now, we all know that the perimeter of a triangle is sum of all the three sides of triangle.

P(ΔABC) = Length of AB+Length of BC+Length of CA

On substituting the values, we get;

$(y+9)+2y+(4y-1)=29\\y+2y+4y+9-1=29\\7y+8=29\\7y=29-8\\7y=21\\y=\frac{21}{7} =3\ cm$

Length of AB = $y+9=3+9=12\ cm$

Length of BC = $2y=2\times3=6\ cm$

Length of CA = $4y-1=4\times3-1=12-1=11\ cm$

Hence the value of y is 3 cm.

8 0

4 years ago

Can someone please solve this ASAP?

olga2289 [7]

The ladder and the wall form a right triangle.
The length is the hypotenuse = 15.
The base = 2*(15/5) = 2*3 = 6

Use pythagorean theorem to find other side of triangle:
$a^2 + b^2 = c^2 \\ \\ a^2 + 6^2 = 15^2 \\ \\ a^2 + 36 = 225 \\ \\ a^2 = 189 \\ \\ a = \sqrt{189} = 3 \sqrt{21}$

8 0

3 years ago

How to solve:<br><br>log8(28k-20)+15=18

yaroslaw [1]

Answer:

k=0.832926

Step-by-step explanation:

6 0

3 years ago