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3 years ago

Please help me with this maths question

Mathematics

1 answer:

Keith_Richards [23]3 years ago

8 0

Answer:

add all of them together then divide bye the number of lines

Step-by-step explanation:

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Hi its my birthday was i correct ? if not please help

s344n2d4d5 [400]

ANSWER: The answer is c) -5 and a very happy birthday to you

7 0

2 years ago

PLEASE HELP ME?! BRAINLIEST ANSWER PLUS EXTRA POINTS! The perimeter of a basketball court is 84 meters and he length is 6 meters

Marina86 [1]

Answer:

I hope this helps you and you have an amazing day the answer

Width=12

Length=30

Step-by-step explanation:

L=2W+6 is

P=2L+2W

84=2(2W+6)+2W

84=4W+12+2W

84=6W+12

6W=84-12

6W=72

W=72/6

W=12 ans. for the width.

L=2*12+6=24+6=30 ans. for the length.

Proof:

84=2*30+2*12

84=60+24

84=84

3 0

3 years ago

Read 2 more answers

(PLEASE HELP PLEASE!! IM GOING TO FAIL) PLEASE HELP ME WITH THESE QUESTIONS!! NOT JUST FOR ME FOR BRAIN! WHO WILL ANSWER FIRST?!

Lina20 [59]

1. A
2. should be 42?
3.???
4.27 apples left
5.B 1/4

7 0

2 years ago

7. If 1 || m and n || q, identify any of the following<br> angles congruent to 6

s344n2d4d5 [400]

The angle congruent to ∠6 are ∠8, ∠3, ∠9 and ∠14

<h3>How to find congruent angles?</h3>

When parallel lines are cut by a transversal, angle relationships are formed. They include corresponding , alternate and many more.

L║m

n ║ q

Therefore, the angles congruent to ∠6 by alternate or corresponding relationship are as follows:

∠6≅∠8≅∠3≅∠9≅∠14

learn more on angles here: brainly.com/question/15443897

#SPJ1

7 0

1 year ago

3x+-2y=-6<br> 5x-2y=7<br> how do i solve this Elimination pls

tatuchka [14]

Answer:

$x=\frac{13}{2}, y=\frac{51}{4}$

Step-by-step explanation:

$We\ are\ given,\\3x-2y=-6\\5x-2y=7\\Considering\ this\ system\ of\ equations,\\Let\ 3x-2y=-6\ be\ E_1\\Let\ 5x-2y=7\ be\ E_2,\\Hence,\\Multiplying\ E2\ with\ -1, we\ get:\\3x-2y=-6\\-1(5x-2y)=7*-1\\Hence,\\3x-2y=-6\\-5x+2y=-7\\Now,\\Lets\ add\ E_1\ and\ E_2\ together\\Hence,\\(3x-2y)+(-5x+2y)=(-6)+(-7)\\Hence,\\3x-2y-5x+2y=-13\\Arranging\ And\ Adding\ Like\ terms,\ we\ have:\\3x-5x-2y+2y=-13\\Hence,\\-2x+0y=-13\\-2x=-13\\x=\frac{-13}{-2}=\frac{13}{2}$

$Now,\ we\ can\ substitute\ x=\frac{13}{2}\ in\ E_1\ or\ E_2,\\But,\\Here,\ we'll\ substitute\ it\ in\ E1,\\Hence,\\Substituting\ x=\frac{13}{2}\ in\ E1,\ we\ have:\\3*\frac{13}{2}-2y=-6\\\frac{39}{2}-2y=-6\\-2y=-6- \frac{39}{2}\\-2y=\frac{-12-39}{2}\\-2y=\frac{-51}{2}\\y=\frac{-51}{2*-2}=\frac{51}{4}\\Hence,\\x=\frac{13}{2}, y=\frac{51}{4}$

4 0

2 years ago