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nalin [4]
11 months ago
10

Find the slope of the line that passes through the following points: (-4,-2) and (-3,5)

Mathematics
1 answer:
stepan [7]11 months ago
6 0
Formula: y2-y1/x2-x1
label your variables by x and y.
subtract y2 from y1, then x2 from x1.
simplify your answer
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The sum of two numbers is x. if one of the numbers is 12, what is the other
nekit [7.7K]
Let y be the unknown number
12+y=x \\ \\ y=x-12

The other number is x - 12
3 0
3 years ago
Suppose you have a light bulb that emits 50 watts of visible light. (Note: This is not the case for a standard 50-watt light bul
natali 33 [55]

Answer:

0.049168726 light-years

Step-by-step explanation:

The apparent brightness of a star is

\bf B=\displaystyle\frac{L}{4\pi d^2}

where

<em>L = luminosity of the star (related to the Sun) </em>

<em>d = distance in ly (light-years) </em>

The luminosity of Alpha Centauri A is 1.519 and its distance is 4.37 ly.

Hence the apparent brightness of  Alpha Centauri A is

\bf B=\displaystyle\frac{1.519}{4\pi (4.37)^2}=0.006329728

According to the inverse square law for light intensity

\bf \displaystyle\frac{I_1}{I_2}=\displaystyle\frac{d_2^2}{d_1^2}

where

\bf I_1= light intensity at distance \bf d_1  

\bf I_2= light intensity at distance \bf d_2  

Let \bf d_2  be the distance we would have to place the 50-watt bulb, then replacing in the formula

\bf \displaystyle\frac{0.006329728}{50}=\displaystyle\frac{d_2^2}{(4.37)^2}\Rightarrow\\\\\Rightarrow d_2^2=\displaystyle\frac{0.006329728*(4.37)^2}{50}\Rightarrow d_2^2=0.002417564\Rightarrow\\\\\Rightarrow d_2=\sqrt{0.002417564}=\boxed{0.049168726\;ly}

Remark: It is worth noticing that Alpha Centauri A, though is the nearest star to the Sun, is not visible to the naked eye.

7 0
3 years ago
What is the value of this expression when t = -12?
Brilliant_brown [7]

Answer:

D

Step-by-step explanation:

I am sorry but I can not give you how I got thinms answer but i do know tgat the answer is correct

5 0
3 years ago
Pleh backwards and you will know what I’m trying to say
8090 [49]

Answer:

Area of triangle = 144 sq.in

Area of rectangle = 312 sq.in

Area of whole figure = 456 sq.in

Step-by-step explanation:

area of truangle =

  • 1/2 × 24 × 12
  • 12 × 12
  • 144

area of rectangle =

  • 24 × 13
  • 312

area of whole fig. = 312 + 144 = 456 sq.in

3 0
2 years ago
Find the surface area of each regular pyramid. Round to the nearest tenth if necessary.
strojnjashka [21]

if you notice the triangle on the left-hand-side, it has a base of 8 ft and a height/altitude of 10.


now, the triangular pyramid has 3 of those triangles standing up, and one at the base lying down, so 4 triangles with that base and altitude. So we can simply find the area of all 4 of those triangles, sum them up and that's the area of the triangular pyramid.


\bf \stackrel{\textit{area of the four triangles}}{4\left[ \cfrac{1}{2}(8)(10) \right]}

8 0
3 years ago
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