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3 years ago

Don’t know how to solve these :l

Mathematics

2 answers:

kumpel [21]3 years ago

7 0

Answer:

452.16

Step-by-step explanation:

Comes down to knowing the Area of a Circle formula- A = πr².

A = area

r = radius, in your case, 12

A = π(12)² = 452.16cm²

xeze [42]3 years ago

3 0

Answer:

452.16 cm²

Step-by-step explanation:

3.14 × 12² = 452.16 cm²

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The right rectangular prism will be sliced perpendicular to its base along the dashed line.

Shkiper50 [21]

A] From the diagram given, the gray shape that has been formed by dashed line is rectangular in shape, thus:
The cross section is a rectangle.

b] The area of the cross section will be given by:
A=length*width
length=8 cm
width=6 cm
hence
A=8×6
A=48 cm²

6 0

3 years ago

Three is a zero of the equation x^3−4x^2−3x+18=0. Which factored form is equivalent to the equation?

Novosadov [1.4K]

Answer:

$x_1=-2,\ x_2=x_3=3\\ \\(x+2)(x-3)^2=0$

Step-by-step explanation:

Consider the equation

$x^3-4x^2-3x+18=0$

The zeros of the equation can be the divisors of 18:

$\pm 1,\ \pm2,\ \pm3,\ \pm 6,\ \pm 9,\ \pm 18$

Check them:

$1^3-4\cdot 1^2-3\cdot 1+18=1-4-3+18=10\neq 0\\ \\(-1)^3-4\cdot (-1)^2-3\cdot (-1)+18=-1-4+3+18=16\neq 0\\ \\2^3-4\cdot 2^2-3\cdot 2+18=8-16-6+18=4\neq 0\\ \\(-2)^3-4\cdot (-2)^2-3\cdot (-2)+18=-8-16+6+18=0$

So, x=-2 is zero. Now

$x^3-4x^2-3x+18\\ \\=x^3+2x^2-6x^2-12x+9x+18\\ \\=x^2(x+2)-6x(x+2)+9(x+2)\\ \\=(x+2)(x^2-6x+9)\\ \\=(x+2)(x-3)^2$

Thus, x=3 is the second root (of multiplicity 2)

6 0

4 years ago

12 thousandths written in scientific notation

Stels [109]

1.2x10^-4

When doing scientific notation the number can't be equal to or bigger than 10 so since it was 12 you had to move the decimal over one so ^-1 then since thousandth is .000 then you have to do ^-3 and then ^-1 + ^-3 is ^-4 and so it comes out 1.2x10^-4... in bad at teaching but hey now you know the answer

8 0

3 years ago

1. TRIATHLON The course for a local

soldier1979 [14.2K]

The biking portion of the triathlon is 11.7 miles far

Step-by-step explanation:

Let us revise the relation between the two legs of a right triangle and

the hypotenuse

Hypotenuse = $\sqrt{(leg_{1})^{2}+(leg_{2})^{2}}$

To find the length of the hypotenuse

1. Square the length of each leg

2. Add the squares of the legs

3. Find the square root of the sum

∵ The legs of the triangle consist of a 4 mile swim and a 11 mile run

∴ $leg_{1}$ = 4

∴ $leg_{2}$ = 11

∵ ( $leg_{1}$ )² = (4)² = 16

∵ ( $leg_{2}$ )² = (11)² = 121

∴ ( $leg_{1}$ )² + ( $leg_{2}$ )² = 16 + 121 = 137

∵ The hypotenuse of the triangle is the biking portion of the event

∵ Hypotenuse = $\sqrt{(leg_{1})^{2}+(leg_{2})^{2}}$

∴ Hypotenuse = $\sqrt{137}$ = 11.7

The biking portion of the triathlon is 11.7 miles far

Learn more:

You can learn more about Pythagoras Theorem in brainly.com/question/1238144

#LearnwithBrainly

5 0

3 years ago

At the school carnival the sixth graders are making directional arrows each arrow is to be painted red how much area needs to be

Anna35 [415]

We can divide arrow in two sections:

A 1 ( rectangle ) = 4 x 5 = 20 sq in.

A 2 ( triangle ) = ( 6 x 3 ) / 2 = 9 sq in.

A = A 1 + A 2 = 20 + 9 = 29 sq in

Answer: B )29 sq in.

7 0

4 years ago

Read 2 more answers