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kipiarov [429]
3 years ago
11

Brook states that the distance on the line is 4 units. Caleb states that the whole line does not have a distance because it cont

inues on forever. Vivian states that the line is 6 units long. Which distance did Brook measure?
Which distance did Vivian measure?
Mathematics
1 answer:
natita [175]3 years ago
8 0

I don't quite understand the question but from what it's given us so far, I can only assume that it is asking which axis the both of them measured?

Vivian measured the X-Axis, as it said she measured it as 6 units long.

Brook only stated that the distance on the line is 4 units, so I can only assume that she measured the Y-Axis.

I  don't know if this helped but if so please give brainliest :D

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The equation c=0.09s gives the amount c (in dollars) of commission a salesperson receives for making a sale of s dollars.
hram777 [196]

Answer:

The independent variable is s

The dependent variable is c

Step-by-step explanation:

Identify the independent and dependent variables:

The equation c = 0.09s gives the amount c (in dollars) of commission a salesperson receives for making a sale of s dollars.

c = 0.09s

Where

c = commission the salesperson makes

s = amount of sales

The variables in the equation are c and s

The independent variable is s

The dependent variable is c because it's value is determined by the amount of sales of the salesperson

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3 years ago
Enter an equation in standard form for the line.<br> Slope is -4, and (-9, -12) is on the line.
AfilCa [17]

Answer:

4x + y +48=0

Step-by-step explanation:

We are here given the slope of the line and one point through which it passes . The slope of the line is -4 and the point is (-9,-12) .

Here we can use the point slope form of the line as ,

\sf\longrightarrow y-y_1 = m(x-x_1)

Substitute the respective values ,

\sf\longrightarrow y - (-12) = -4\{ x -(-9)\}

Simplify LHS and RHS ,

\sf\longrightarrow y + 12 = -4( x +9)

Open the brackets in RHS ,

\sf\longrightarrow y + 12 = -4x -36

Add 36 and 4x to both sides ,

\sf\longrightarrow \underline{\boxed{\orange{\sf  4x + y + 48 =0}}}

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4 years ago
Read 2 more answers
Flaws in concrete beams follow a Poisson process. Beams fabricated by process A have flaw rates of 10/meter while beams fabricat
Kay [80]

Answer:

P(A | Y = 8) =  0.633

Step-by-step explanation:

It is really a simple and interesting question, as it involves the Poisson distribution and probability.

First of all, let's try to understand the problem statement clearly. It says that there are two process by which beams are made, namely A and B.

It further states that, beam made by process A has = 10 flaws per meter.

Beam made by process B has = 5 flaws per meter.

Finally, it says that from a yard containing equal numbers of process A and process B beans, one beam is randomly selected and 1 - meter of it is inspected. And they have found 8 flaws in it.

We now, have to find out the probability that the inspected beam is from process A.

For this,

Let's suppose, Y is no. of flaws

So,

P (Y=8|A) = \frac{e^{-10}. 10^{8}  }{8!}

where , e = Euler's Constant = 2.71828

P (Y=8|A) = 0.11

Similarly for process B

P (Y=8|B) = \frac{e^{-5}. 5^{8}  }{8!}

P (Y=8|B) = 0.06

As, we know from the problem statement that there are equal numbers of process A and process B beams.

So, the probability of A = Probability of B = 0.5

P(A) = 0.5

P(B) = 0.5

We need to find, P(A|Y=8) and for this we need to find the P(Y=8) first.

Using the law of total probability:

P(Y=8) =  P(Y = 8 |A) P(A) + P(Y = 8|B) P(B)

Plug in the values:

P(Y=8) = (0.11 x 0.5) + (0.06 x 0.5)

P(Y=8) = 0.088

Now, by applying Bayes Theorem, we can find the required probability:

P(A | Y = 8) = P(Y = 8 | A) P(A) / P(Y = 8)

8 flaws are found, the probability the inspected beam was fabricated using process A is :

P(A | Y = 8) = 0.11 x 0.5 / 0.088

P(A | Y = 8) =  0.633

Furthermore,

8 flaws are found, the probability the inspected beam was fabricated using process B is :

P(B | Y = 8) = 1-P(A | Y = 8)

P(B | Y = 8) = 1 - 0.633

P(B | Y = 8) = 0.367

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3 years ago
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bearhunter [10]
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