Question

Can someone help me simplify the expression? Show your work :) ! Picture below !!!

Answer 1

Answer:

$$\sqrt[3]{27x^6y^4}=3 x^2\sqrt[3]{y^4}$$

Step-by-step explanation:

$\sqrt[3]{27x^6y^4}= \sqrt[3]{3^3x^6y^4}\\\sqrt[3]{27x^6y^4}=\sqrt[3]{3^3} \sqrt[3]{x^6} \sqrt[3]{y^4}$

therefore,

$\sqrt[3]{27x^6y^4}=3 x^2\sqrt[3]{y^4}$