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Dominik [7]
3 years ago
13

Which expression is equivalent to the given expression after using the distributive property?

Mathematics
2 answers:
Fed [463]3 years ago
5 0

Answer:

  • 9 · x + 9 · 3 + 15x

Step-by-step explanation:

<u>Given</u>

  • 9(x + 3) + 15x

<u>Opening parenthesis, using distributive property of multiplication</u>

  • 9*x + 9*3 + 15x

Correct option is the last one

Jobisdone [24]3 years ago
3 0

Answer:

Last one I think

Step-by-step explanation:

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Suppose triangle TIP and triangle TOP are isosceles triangles. Also suppose that TI=5, PI=7, and PO=11. What are all the possibl
Ede4ka [16]
<h3>Two answers: 5, 7</h3>

====================================================

Explanation:

A drawing may be helpful to see what's going on. Check out the diagram below. This is one way of drawing out the two triangles. The locations of the points don't really matter, and neither does the the orientation of how you rotate things. What does matter is we have the right points connected to form the segments mentioned.

----------

For now, focus on triangle TIP only. In order to have this be isosceles, we must make TP = 5 or TP = 7.

If TP = 5, then it's the same length as TI.

If TP = 7, then it's the same length as PI.

In either case, we have exactly two sides the same length (the other side different) which is what it means for a triangle to be isosceles.

----------

Let's consider triangle TOP. For it to be isosceles, we must have two sides the same length. We already locked in TP to be either 5 or 7 in the previous section above. So there's no way that TP could be 11 units long to match up with PO = 11.

If TP = 5, then OT must also be 5 units long so that triangle TOP is isosceles.

If TP = 7, then OT = 7 for similar reasoning.

Either way, TP only has two choices on what it could be.

----------

In short, we basically just write the first two values given to us to get the two triangles to be isosceles. We can't use TP = 11 as it would make triangle TIP to be scalene (all sides are different lengths).

7 0
3 years ago
A football team was training for four hours. During the first hour, they practiced for 5/8 of an hour. During the second hour, t
Leviafan [203]

Answer: 2 19/24 hours was spent in practising.

Step-by-step explanation:

During the first hour, they practiced for 5/8 of an hour. During the second hour, they practiced for 2/3 of an hour. This means that the total time for which they practiced in the first 2 hours would be

5/8 + 2/3 = 31/24 hours

During the last two hours, they first practiced for 3/5 of an hour, took a 1/2 hour break and then practiced the rest of the time. This means that the rest of the time for which they practiced is

2 - (3/5 + 1/2) = 2 - 11/10 = 9/10

Therefore, the time they spent practicing in total would be

31/24 + 3/5 + 9/10 = 67/24 =

2 19/24 hours

7 0
3 years ago
I'm solving for UW. And we're using pythagorean theorem.​
Alik [6]
UW = 45
a squared + b squared = c squared
- 6^2 + x^2 = 9^2
- 36 + x = 81
- (subtract 36 from both sides)
- x = 45

i'm pretty sure this is right and i hope it helps you!
7 0
3 years ago
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Mrrafil [7]
It has a surface area to volume ratio of 1:1
3 0
3 years ago
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What is the difference of the polynomials?
alina1380 [7]

Answer:

Step-by-step explanation:

C is the right answer

8 0
3 years ago
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