Question

How do you solve 3x+1 = 15 for x using the change of base formula log base b of y equals log y over log b?

Answer 1

Anwser is 14/3

Subtract the 1 and divide by 3

Answer 2

Answer with explanation:

The given equation in single variable x, is

⇒3 x+1=15

Subtracting 1 from both sides

⇒ 3 x +1 -1 = 15- 1

⇒3 x =14

Dividing both sides by, 3 we get

$x=\frac{14}{3}\\\\x=log_{10}\frac{14}{3}\\\\ \log_{a}b=\frac{\log b}{\log a}$

Because ,log 10=1