Answer:
25% of the progeny with genotype S3S4 is expected to express 5 units of color
Explanation:
<u>Available data</u>:
- Skin color in a certain species of fish is inherited via a gene with four different alleles
- allele S1 confers one unit of color, S2 has two units, S3 has three units, and S4 confers four units.
Cross:
Parentals) S1 S3 x S2S4
Gametes) S1 S3 S2 S4
Punnett square) S1 S3
S2 S1S2 S2S3
S4 S1S4 S3S4
F1) 1/4 = 25% of the progeny is expected to be S1S2, expressing 3 units of color ⇒ allele S1 provides one unit, allele S2 provides two units of color
1/4 = 25% of the progeny is expected to be S2S3, expressing 5 units of color ⇒ allele S2 provides two units, allele S3 provides three units of color
1/4 = 25% of the progeny is expected to be S1S4, expressing 5 units of color ⇒ allele S1 provides one unit, allele S4 provides four units of color
1/4 = 25% of the progeny is expected to be S3S4, expressing 7 units of color ⇒ allele S3 provides three units, allele S4 provides four units of color
25% of the progeny with genotype S3S4 is expected to express 5 units of color
Answer:
The amount of solar energy in a given area is greater at the equator than in an equal area at the poles, which is why the equator temperature is warmer than the polar temperatures.
Explanation: Hope this helps!!
<h2>Answer:</h2>
<u>The pituitary gland is called the master gland of the human body. </u>
<h2>Explanation:</h2>
The pituitary gland is called the master gland of the endocrine system present in the human body because this gland controls all the functions of many endocrine glands. The pituitary gland is no bigger than a pea, and is located at the base of the brain which hangs by a thin stalk from the hypothalamus.
Answer:
The enzyme is the pyruvate kinase
Explanation:
The designated enzyme can only grow in pyruvate or in ethanol. They are said to be in anaerobic conditions. If the end product of glycolysis is pyruvate and the enzyme that transforms phosphoenol pyruvate into pyruvate is called pyruvate kinase. In a reaction under anaerobic conditions, the pyruvate is transformed into ethanol. So if the pyruvate kinase enzyme is mutated, pyruvate cannot be transformed into ethanol and Saccharomyces cerevisiae could not survive in that medium.
The biome with the most diverse communities of organisms is the rainforest.