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ladessa [460]
3 years ago
5

3) 12 - 24 = 4) 810 - 23 = 5) 23 - 14 =

Mathematics
1 answer:
Xelga [282]3 years ago
3 0
12 - 24 = -12

810 - 23 = 787

23 - 14 = 9
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If m proportional to n and m=5 when n=4.what is the valuue of m?when n=18
Dovator [93]

Answer:

m=22.5

Step-by-step explanation:

m is proportional to n means there is some constant k such that:

m=kn

If m=5 when n=4 then we have the following equation to solve for our constant k:

5=k(4)

5=4k

Divide both sides by 4:

5/4 =k

So k=5/4 no matter what (m,n) pair they give you where the equation is m=kn.

m=(5/4)n

What is m when n=18?

m=(5/4)(18)

m=(5/2)(9)

m=45/2

m=22.5

5 0
3 years ago
Sal invests $16,000 at age 35. He hopes the investment will be worth $320,000 when he turns 40. If the interest compounds contin
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59.9%

Sorry I don’t have time to explain in the middle of an exam

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3 years ago
2 square times 3 square times 5 square is the prime factorization of what composite number?
yanalaym [24]
Is this suppose to be for elementary because I'm in middle school and I got 900 2^2*3^2*5^2=900
7 0
4 years ago
What is the solution of ? x = –6 or x = –3
quester [9]

Answer:

x=-9

Step-by-step explanation:

8 0
3 years ago
A social psychologist wants to know whether students' performance on a problem solving task is lowered by having other people lo
Orlov [11]

Answer:

Yes, there is sufficient evidence to conclude that performance on the problem solving task is lowered by having onlookers.

Step-by-step explanation:

Null hypothesis: The performance on the problem solving task is lowered by having onlookers.

Alternate hypothesis: The performance on the problem solving task is not lowered by having onlookers.

Test statistic (t) = (sample mean - population mean) ÷ (sample sd/√n)

sample mean = 89.8

population mean = 89.1

sample sd = √sample variance = √84.6 = 9.198

n = 21

Degree of freedom = n-1 = 21-1 = 20

Assuming a 5% significance level

The test is a two-tailed test. Critical values corresponding to 20 degrees of freedom and 5% significance level are -2.086 and 2.086

Test statistic (t) = (89.8 - 89.1) ÷ (9.198/√21) = 0.7 ÷ 2.007 = 0.349

Conclusion:

Fail to reject the null hypothesis because the test statistic 0.349 falls within the region bounded by the critical values.

There is sufficient evidence to conclude that performance on the problem solving task is lowered by having onlookers.

4 0
3 years ago
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