Answer:
5sqrt3
Step-by-step explanation:
Using the pythagorean theorem, we have a^2+4^2=9^2
a^2 + 16 = 81
a^2 = 75.
a = sqrt75.
75 = 25*3. 25 is a perfect square, so sqrt75 = 5sqrt3
Answer:
1. x = 2
2. x = 61/25
Step-by-step explanation:
Solve for x:
5 (x - 2) - 3 (2 - x) = 0
-3 (2 - x) = 3 x - 6:
3 x - 6 + 5 (x - 2) = 0
5 (x - 2) = 5 x - 10:
5 x - 10 + 3 x - 6 = 0
Grouping like terms, 5 x + 3 x - 10 - 6 = (3 x + 5 x) + (-6 - 10):
(3 x + 5 x) + (-6 - 10) = 0
3 x + 5 x = 8 x:
8 x + (-6 - 10) = 0
-6 - 10 = -16:
8 x + -16 = 0
Add 16 to both sides:
8 x + (16 - 16) = 16
16 - 16 = 0:
8 x = 16
Divide both sides of 8 x = 16 by 8:
(8 x)/8 = 16/8
8/8 = 1:
x = 16/8
The gcd of 16 and 8 is 8, so 16/8 = (8×2)/(8×1) = 8/8×2 = 2:
Answer: x = 2
_____________________________
Solve for x:
Solve for x:
3 (2 x - 7) + (7 x + 2)/3 = 0
Put each term in 3 (2 x - 7) + (7 x + 2)/3 over the common denominator 3: 3 (2 x - 7) + (7 x + 2)/3 = (9 (2 x - 7))/3 + (7 x + 2)/3:
(9 (2 x - 7))/3 + (7 x + 2)/3 = 0
(9 (2 x - 7))/3 + (7 x + 2)/3 = (9 (2 x - 7) + (7 x + 2))/3:
(9 (2 x - 7) + 2 + 7 x)/3 = 0
9 (2 x - 7) = 18 x - 63:
(18 x - 63 + 7 x + 2)/3 = 0
Grouping like terms, 18 x + 7 x - 63 + 2 = (18 x + 7 x) + (2 - 63):
((18 x + 7 x) + (2 - 63))/3 = 0
18 x + 7 x = 25 x:
(25 x + (2 - 63))/3 = 0
2 - 63 = -61:
(25 x + -61)/3 = 0
Multiply both sides of (25 x - 61)/3 = 0 by 3:
(3 (25 x - 61))/3 = 3×0
(3 (25 x - 61))/3 = 3/3×(25 x - 61) = 25 x - 61:
25 x - 61 = 3×0
0×3 = 0:
25 x - 61 = 0
Add 61 to both sides:
25 x + (61 - 61) = 61
61 - 61 = 0:
25 x = 61
Divide both sides of 25 x = 61 by 25:
(25 x)/25 = 61/25
25/25 = 1:
Answer: x = 61/25
Answer:
+1 and -1
Step-by-step explanation:
The function in this problem is:
First of all, we have to define the domain of the function, which is the set of values of x for which the function is defined.
In order to find the domain, we have to require that the denominator is different from zero, so
which means:
So the domain is all values of x, except from 4 and -7.
Now we can solve the problem and find the zeros of the function. The zeros can be found by requiring that the numerator is equal to zero, so:
This is verified if either one of the two factors is equal to zero, therefore:
and
We see that both values are part of the domain, so they are acceptable values: so the zeros of the function are +1 and -1.
The question isn’t visible please ask it again I’m sorry :(
Both are 3.
The first one EBF is not equal to ABC because EBF is half of ABC not the entirety of it.
The second one is 3 because is A=B then A to C would be the same as going B to C.
