Find the powers 
$a^{2}=5+2 \sqrt{6}$
$a^{3}=11 \sqrt{2}+9 \sqrt{3}$
The cubic term gives us a clue, we can use a linear combination to eliminate the root 3 term $a^{3}-9 a=2 \sqrt{2}$ Square $\left(a^{3}-9 a\right)^{2}=8$ which gives one solution. Expand we have $a^{6}-18 a^{4}-81 a^{2}=8$ Hence the polynomial $x^{6}-18 x^{4}-81 x^{2}-8$ will have a as a solution.
Note this is not the simplest solution as $x^{6}-18 x^{4}-81 x^{2}-8=\left(x^{2}-8\right)\left(x^{4}-10 x^{2}+1\right)$
so fits with the other answers.
Answer:
The height of triangle EFG is 9 units
Step-by-step explanation:
see the attached figure to better understand the problem
step 1
Find the area of a square ABCD
The area of a square is equal to
where
b is the length side of the square
we have
substitute
step 2
Find the height of triangle EFG
The area of triangle EFG is equal to
where
b is the base of triangle
h is the height of triangle
we have
---> area of triangle EFG is the same that the area of square ABCD
substitute the given values in the formula
solve for h
therefore
The height of triangle EFG is 9 units
Answer:
q = ³√64
(cube root 64 )
explanation :
we have to find the value of q but it's given q³ so to find the value of only q we send ³ to other side and it turns into cube root
for example :
like when it's q² = 64 it will be q = ²√64
