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Zolol [24]
2 years ago
6

Please help I don't understand ​

Mathematics
1 answer:
Bond [772]2 years ago
3 0

Answer:

mx+b

Step-by-step explanation:

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Which equation is y = –3x2 – 12x – 2 rewritten in vertex form?
WARRIOR [948]
Y=-6-12x-2
y=-6-12x-2
y=-8-12x
y=-8-12x
and these are real numbers
7 0
3 years ago
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How large a sample should be selected to provide a 95% confidence interval with a margin of error of 6? Assume that the populati
marshall27 [118]

Using the z-distribution, it is found that a sample of 171 should be selected.

<h3>What is a z-distribution confidence interval?</h3>

The confidence interval is:

\overline{x} \pm z\frac{\sigma}{\sqrt{n}}

The margin of error is:

M = z\frac{\sigma}{\sqrt{n}}

In which:

  • \overline{x} is the sample mean.
  • z is the critical value.
  • n is the sample size.
  • \sigma is the standard deviation for the population.

For this problem, the parameters are:

z = 1.96, \sigma = 40, M = 6

Hence we solve for n to find the needed sample size.

M = z\frac{\sigma}{\sqrt{n}}

6 = 1.96\frac{40}{\sqrt{n}}

6\sqrt{n} = 40 \times 1.96

\sqrt{n} = \frac{40 \times 1.96}{6}

(\sqrt{n})^2 = \left(\frac{40 \times 1.96}{6}\right)^2

n = 170.7.

Rounding up, a sample of 171 should be selected.

More can be learned about the z-distribution at brainly.com/question/25890103

#SPJ1

4 0
2 years ago
4(8x−1) = 19+32x
Fantom [35]

<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3

Answer:

Let's solve your equation step-by-step.

4 ( 8x − 1 ) = 19 + 32x

Step 1: Simplify both sides of the equation.

4 ( 8x − 1 ) = 19 + 32x

( 4 ) ( 8x ) + ( 4 ) ( −1 ) = 19 + 32x ( Distribute )

32x + −4 = 19 + 32x

32x − 4 = 32x + 19

Step 2: Subtract 32x from both sides.

32x − 4 − 32x = 32x + 19 − 32x

−4 = 19

Step 3: Add 4 to both sides.

−4 + 4 = 19 + 4

0 = 23

Answer:

There are no solutions.

<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3

5 0
2 years ago
Read 2 more answers
I dont quite understand this.. Check the picture and help
wariber [46]

5) 74.925

6) 470

i think this is correct but i'm not completely sure

6 0
3 years ago
Look at the attachment<br>Simplified it too <br>pls take it seriously ​
Phantasy [73]

\\ \rm\rightarrowtail \dfrac{sin(180+A)+2cos(180+A).cos(A-180)}{2cos^2(360+A)-cos(-A)}

\\ \rm\rightarrowtail \dfrac{-sinA+2(cos^2A-sin^2A)}{2cos^2A-cosA}

\\ \rm\rightarrowtail \dfrac{-sinA+2cos^2A-2sin^2A}{cosA(2cosA-1)}

\\ \rm\rightarrowtail \dfrac{-sinA+2-2sin^2A-2sin^2A}{cosA(2cosA-1)}

\\ \rm\rightarrowtail \dfrac{-sinA-4sin^2A}{cosA(2cosA-1)}

\\ \rm\rightarrowtail \dfrac{-sinA(4sinA-1)}{cosA(2cosA-1)}

\\ \rm\rightarrowtail -tanA\left(\dfrac{4sinA-1}{2cosA-1}\right)

5 0
1 year ago
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