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3 years ago

Is there a method that could prove that these two triangles are similar?

Mathematics

1 answer:

dalvyx [7]3 years ago

4 0

Answer:

A Yes, a sequence of dilations and rigid motions carries one triangle onto the other

Step-by-step explanation:

Since two angles are marked with the same measures in each triangle, the triangles are similar by the AA postulate with no further action.

By some accounts it seems to be necessary to lay one figure on top of the other to demonstrate similarity. In order to do that, the smaller triangle would need to be dilated and translated (a rigid motion) to make it occupy the same space as the larger triangle.

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Use the remainder theorem to find the remainder for (x ^5 + 32) divided by (x+2) and state whether or not the binomial is a fact

marta [7]

$x+2$ is a factor of $x^5+32$ because (by the remainder theorem) the remainder upon dividing $x^5+32$ by $x+2$ is $(-2)^5+32=0$ .

There's also the sum of fifth powers formula,

$a^5+b^5=(a+b)(a^4-a^3b+a^2b^2-ab^3+b^4)$

3 0

3 years ago

Read 2 more answers

-13.9+(-12.8) evaluate the answer

taurus [48]

Answer:

Step-by-step explanation:

=-13.9+(-12.8)

=-13.9-12.8

8 0

2 years ago

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Does 26/3 equal 182/21

brilliants [131]

Answer: Yes, they are equal

Step-by-step explanation:

Quick statement: To find equivalent fractions, multiply or divide them by the same number.

In this particular example, you can divide 182 by 7 and get 26 and 21 by 7 to get 3. This symbols that they are equal. If you try the inverse operation (multiplication), you could multiply 26 by 7 and get 182. Same goes for 21 and 3: you multiply 3 by 7 to get 21. Just remember to multiply or divide the two numbers (numerator and denominator) by the same number to get an equivalent fraction.

3 0

3 years ago

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What is the sign of 3x y3xy3, x, y when x>0x>0x, is greater than, 0 and y<0y<0y, is less than, 0?

jekas [21]

Answer:

$Negative$

Step-by-step explanation:

$We\ have\ to\ find\ sign\ of\ 3xy^3\\\\x>0\ and\ y0,y$

4 0

3 years ago

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Jen Butler has been pricing Speed-Pass train fares for a group trip to New York. Three adults and four children must pay $ 132.

laiz [17]

Let a=price of adult ticket
let c=price of a child's ticket
start out by writing the following system of equations:
3a+4c=132
2a+3c=94
then, multiply the first equation by 2, and the second equation by 3 to get the following system of equations:
6a+8c=264
6a+9c=282
subtract the like terms to get the following equation:
-c=-18
divide both sides by -1 to get rid of the negative to get the price of a child's ticket to be $18. to find the price of an adult ticket, pick one of the original equations to substitute the 18 in for c to find a. for example:
2a+3c=94
2a+3(18)=94
2a+54=94
-54 -54
2a=40
2 2
a=20

or if you decide to use the other equation:
3a+4c=132
3a+4(18)=132
3a+72=132
-72 -72
3a=60
3 3
a=20
either way, you still get an adults ticket to be $20 and a child's ticket to be $18.

8 0

3 years ago