Question

One number is 10 times as large as another, and their difference is 81. Find the numbers.

Answer 1

Answers:

The smaller number is x, this means that the larger number is 10x

The smaller number is 9

The larger number is 90

Explanation:

We are given that the smaller number is x and that the larger number is 10 times the smaller one.

This means that:

larger number = 10 * x = 10x

Now, we know that the difference between them is 81

This means that:

larger number - smaller number = 81

10x - x = 81

9x = 81

x = 9

Based on the above:

The smaller number = x = 9

The larger number = 10x = 10 * 9 = 90

Hope this helps :)

Answer 2

Let x = smaller number.

So for this, our larger number equation is 10x, and to find what x is, we have to set it to 81. Our equation will be $10x-x=81$

Firstly, combine like terms: $9x=81$

Next, divide 9 on both sides of the equation, and your answer should be $x=9$ .

Now that we know that the smaller number is 9, just multiply that by 10 to get 90.

And in short, the smaller number is 9 and the larger number is 90.

If x represented the smaller number, then the larger number is 10x.