He will have a 1/531,441 chance of winning next week.
There are 10 balls in each container; for 6 containers, this gives us 10^6 = 1,000,000. There is 1 correct combination of balls, so his chance the first week is 1/1,000,000.
The second week, 1 ball is removed from each container; this will give us 9^6 = 531,441 chances. There is 1 correct combination, so he will have a 1/531,441 chance of winning.
Answer:
Step-by-step explanation:
Total number of antenna is 15
Defective antenna is 3
The functional antenna is 15-3=12.
Now, if no two defectives are to be consecutive, then the spaces between the functional antennas must each contain at most one defective antenna.
So,
We line up the 13 good ones, and see where the bad one will fits in
__G __ G __ G __ G __ G __G __ G __ G __ G __ G __ G __ G __G __
Each of the places where there's a line is an available spot for one (and no more than one!) bad antenna.
Then,
There are 14 spot available for the defective and there are 3 defective, so the arrange will be combinational arrangement
ⁿCr= n!/(n-r)!r!
The number of arrangement is
14C3=14!/(14-3)!3!
14C3=14×13×12×11!/11!×3×2
14C3=14×13×12/6
14C3=364ways
Answer:
$1,363
Step-by-step explanation:
i googled it .... but its $2000 - $637...you get $1363
Answer:
8ac+3b-7a
Step-by-step explanation:
2ac+6ac+4b-b-7a=
