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AlekseyPX
3 years ago
11

In a weekly lottery, ten ping-pong balls numbered 0 to 9 are placed in each of six containers, and one ping-pong ball is drawn f

rom each container. To win the prize, a participant must correctly identify the ping-pong ball that is drawn from each of the six containers. If Juan played the lottery last week and didn’t win, what is the probability that he will win this week?
Mathematics
2 answers:
sukhopar [10]3 years ago
6 0
He will have a 1/531,441 chance of winning next week.

There are 10 balls in each container; for 6 containers, this gives us 10^6 = 1,000,000.  There is 1 correct combination of balls, so his chance the first week is 1/1,000,000.

The second week, 1 ball is removed from each container; this will give us 9^6 = 531,441 chances.  There is 1 correct combination, so he will have a 1/531,441 chance of winning.
Fynjy0 [20]3 years ago
5 0

Answer:

The answer is <em>A. 1/1000000</em>

Step-by-step explanation:

Last week’s lottery has no effect on this week’s lottery.

In other words, last week’s lottery and this week’s lottery are independent events.

For this reason, the fact that Juan didn’t win last week’s lottery has no influence on the probability that he will win this week’s lottery.

In this week’s lottery, the drawing from each container is an independent event, so the probability that Juan will win this week is  

1/10  x  1/10 x 1/10 x 1/10 x 1/10 x 1/10 = <em>1/1000000</em>

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FIND THE MEASUREMENT OF THE MISSING ANGLES ON THE GIVEN FIGURE BELOW AND STATE YOUR REASON
marusya05 [52]

Answer:

Step-by-step explanation:

1) ∠1 +  ∠2 = 180    {linear pair}

    105 +∠2 = 180

            ∠2 = 180 - 105

            ∠2 = 75°

Reason: Linear pair

2) ∠3 = ∠1          {Vertically opposite angles are congruent}

   ∠3 = 105

Reason: Vertically opposite angles are congruent

3 0
2 years ago
The average rate of change of f from 2 to 3
ella [17]

For a function of f, the average rate of change can be found as follows:


ARC=\frac{f(x_{2})-f(x_{1})}{x_{2}-x_{1}}


So, this problem asks for the Average Rate of Change of f from x_{1}=2 to x_{2}=3. In this way, we need to find f(x_{1}) \ and \ f(x_{2}). As you can see above, we have the graph of f(x), so we can find these values. Thus, from the graph:


f(x_{1})=4 \\ f(x_{2})=1


Therefore:


ARC=\frac{1-4}{3-2} \\ \\ \therefore \boxed{ARC=-3}

3 0
3 years ago
A flash disk has the capacity of storing 1 megabyte of data. How many kilobytes of data can be stored in the same flash disk​
Luden [163]

For this sort of problem, you need to be familiar with prefixes.

So:

megabyte = 1 *10^6 bytes

kilobyte = 1*10^3 bytes

and a regular byte would just be 1

Now, you will need to do a conversion:

1megabyte*\frac{1*10^6bytes}{1megabyte}*\frac{1*10^{-3}kilobyte}{1byte}

I'm going to explain this just in case, but we convert megabytes to regular bytes in the first half by using the information I gave you above. (In one megabyte, there are 1*10^6 bytes!)

In the second fraction thought, remember one kilobyte is 1*10^3 bytes. However, you usually only see one of each thing on the bottom of fractions, so you need to add a negative sign to the 3. (technically you could just do \frac{1kilobyte}{1*10^3bytes}, but I think it is more correct to do write it out how I did).

*** They do equal the same thing though! Do whichever way is easier for you!

Now, your answer should be:

10^3 kilobytes (1000 kilobytes)

Hope this helped!

6 0
3 years ago
BRAINLIEST Look at the pattern and decide what number comes next.<br> 2 7 3 8 4 9 5 ?
baherus [9]

Answer:

10

Step-by-step explanation:

2 + 5 = 7

3 + 5 = 8

4 + 5 = 9

5 + 5 = 10

4 0
3 years ago
Read 2 more answers
Can anyone solve 9, 10, 11, 12, and 13 I'm stuck on those problems, I already solved 14, 15, and 16 on paper.
ddd [48]

Answer:

9. x>-4 or x≥1

10. a<2 or a≥-5

11. v≤7 or v≥-4

12. k≥5 or k<8

13. n>6.8 and n≤9

Step-by-step explanation:

9. -2x-7>1

-2x>8

x>-4

x-2≥-1

x≥1

10.a/-2 <-1

a<2

-4a+3≥23

-4a≥20

a≥-5

11. 6v+38≤-4

6v≤-42

v≤7

2(v+3)≥-2

2v+6≥-2

2v≥-8

v≥-4

12. 4(1-k)≥-16

4-4k≥-16

-4k≥-20

k≥5

7-6k<-41

-6k<-48

k<8

13. 10n-9>-59

10n>-68

n>6.8

n-6≤3

n≤9

4 0
2 years ago
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