9514 1404 393
Answer:
(a) 90°, 90°
(b) 5, 1
(c) 10°, 20°
(d) 10°, 20°, 150°
Step-by-step explanation:
You need to consider ways in which each statement might not apply.
(a) An obtuse angle is greater than 90°. If both angles are 90°, then neither is obtuse.
counterexample: m∠1 = 90°, m∠2 = 90°
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(b) If the perimeter is 12, the sum of the side lengths must be 6. There are many ways to get two numbers that have a sum of 6. Here's one:
counterexample: length = 5, width = 1
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(c) All that is required is that the sum of angles be 30°. They don't have to be equal.
counterexample: m∠ABC = 10°, m∠CBD = 20°
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(d) We know the three angles of a triangle have a sum of 180°, but that does not require it to be an acute triangle. A triangle can also be right or obtuse.
counterexample: m∠P = 10°, m∠Q = 20°, m∠R = 150°
Answer:
<em>45 possible connections</em>
<em />
Step-by-step explanation:
The general equation for finding the possible number of connections in a network is given as
where n is the number of computers on the network.
for 4 computers, we'll have
= 
= 6
for 5 computers, we'll have
= 
= 10.
therefore, for 10 computers, we will have
= 
= <em>45 possible connections</em>
Answer:
<h2>Jordan age = 31 years</h2><h2>Anna age = 19 years</h2>
<u>Step-by-step explanation:</u>
let Jordan age be <u>X</u> & Anna age be <u>Y</u>
so,
Jordan is 12 years older than Anna.
x = y + 12 ......... (1)
The sum of their ages is 50.
x + y = 50 ........ (2)
putting value of x from (1) into (2)
x + y = 50
(y + 12) + y = 50
2y + 12 = 50
2y = 50 - 12
2y = 38
y = 38÷2
y = 19
putting value of y in (2)
x + y = 50
x + 19 = 50
x = 50 - 19
x = 31
so,
Jordan age = 31 years
Anna age = 19 years
Here we're dividing a fraction (5/8) by another fraction. We could obtain the same result by inverting the divisor (2/5) and then multiplying (5/8) by (5/2).
The product is 25/16.
Thus, 2/5 divides into 5/8 25/16 times, or 1 9/16 times.
The answer is C because the 2x outside of the brackers must be negative to produce the beginning term. The next terms are positive and two negatives make a positive, therefore we can conclude that there must be a negative inside the brackets too.
