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statuscvo [17]
3 years ago
15

What are the domain and the range of the relation?

Mathematics
1 answer:
attashe74 [19]3 years ago
7 0
I am pretty sure the answers are A and C
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Two congruent 30-60-90 triangles are placed,as shown,so that they overlap partly and their hypotenuses coincide. If the hypotenu
Ede4ka [16]

Answer: The area common to both triangle is 31.77 sq. cm.

Step-by-step explanation:

Since we have given that

30-60-90 triangles are placed.

So, the ratio of sides would be

1:\sqrt{3}:2

Since Hypotenuse = 12 cm

So, it becomes,

2x=12\\\\x=\dfrac{12}{2}=6

So, Base would be

x=6\ cm

and Perpendicular would be

\sqrt{3}x=6\sqrt{3}

So, Area common to the both triangles would be

\dfrac{1}{2}\times base\times height\\\\=\dfrac{1}{2}\times 6\times 6\sqrt{3}\\\\=18\sqrt{3}\\\\=31.177

Hence, the area common to both triangle is 31.77 sq. cm.

4 0
3 years ago
2. Use the graph of y=-X2 - 2x + 3 to solve
natita [175]

Answer:

Solution is x=-3 and x =1, because that is zero od function y=-x^2-2x+3

8 0
3 years ago
Positive and negative relationships are both examples of linear relationships
NARA [144]

Answer: A. True.

Step-by-step explanation:

A relationship is linear when the points on a scatterplot follow a somewhat straight line pattern. This is the relationship that we will examine. Linear relationships can be either positive or negative. Positive relationships have points that incline upwards to the right. As x values increase, y values increase.

4 0
2 years ago
What are the amplitude, period, phase shift, and midline of f(x) = 2 sin(x + π) − 4?
Alex17521 [72]
Given that f(x)=2sin(x+π), the standard form of sine function is y=A=sin(Bx+C), with:
A=amplitude
2π/B=period
C/B=phase-shift
A=2=amplitude
B=1
period=2π/B=2π/1=2π
C=2π/1=2π


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3 years ago
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1 11 21 31 41 51 61 71 81 91
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3 years ago
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