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BartSMP [9]
3 years ago
5

Pleaase help!Find h. 11 in. h = ✓ [?] in. 14 in Enter​

Mathematics
1 answer:
Aleksandr [31]3 years ago
3 0

Answer:

h=8.48\ \text{inches}

Step-by-step explanation:

Given that,

Radius of cone, r = 7 inches

Slant height of the cone, l = 11 inches

We need to find the height of the cone. Let the height be h. Using trigonometry to find it as follows :

h^2+r^2=l^2\\\\h=\sqrt{l^2-r^2}\\\\h=\sqrt{11^2-7^2}\\\\h=8.48\ \text{inches}

So, the height of the cone is equal to 8.48\ \text{inches}.

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in a sponsored walk for charity, 560 students joined. only 0.72% finished the walk. how many students completed the walk?
Keith_Richards [23]

Answer:

About 4 students completed the walk.

Step-by-step explanation:

0.72%=0.0072

0.0072*560=4.032

7 0
3 years ago
Can someone please help me with this question.
rusak2 [61]
25x25+20x25+20x15+15x25=1800 the answer is D.
5 0
4 years ago
Solve the equation for x by graphing -2x + 3 = -3(-x) - 2
adoni [48]

Answer:

  x = 1

Step-by-step explanation:

There are a couple of ways to solve this. One is to graph the left side of the equation, graph the right side of the equation, and look for the point where those graphs intersect. It is at x = 1. The first attached graph shows this solution.

__

Another method for solving such an equation is to subtract one side from the other and look for the value of x that makes the resulting expression zero.

  (-2x +3) -(-3(-x) -2) = 0

A graphing calculator doesn't need to have this simplified. If it is simplified, it becomes ...

  -5x +5 = 0

So, the graphed line is y = -5x+5. Its x-intercept is x=1, the solution of the original equation. The graph of this is shown in the second attachment.

6 0
3 years ago
Pls help me its really late
BigorU [14]
The answer is 11/16 the probability will be very high
6 0
3 years ago
What is 3,745 gram in kilograms
maw [93]

3.745 Kilograms.

1 Gram is equivalent to .001 Kilograms.

So in order to convert 3,745 Grams to Kilograms, we would do .001 Grams * 3745 Kilograms

3 0
3 years ago
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