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3 years ago

How is estimation helpful when adding and subtracting decimals

2 answers:

6 0

It's helpful because let's say you have $3.23 and you need to give someone $1.00 then you would need to subtract then what way you will know what you need to do and how many money u have left

Gnesinka [82]3 years ago

4 0

Its a lot easier to do 1.200 - .200. Than to do 1.248- .239. How I see it, estimating always gives you something to fall back on or to help see if your exact answer is accurate

You might be interested in

describe the transformations that occur from the parent function f(x) =x^2 to the function g(x)=2(x+1)^2-7

irinina [24]

translate 7 units down. One to the left. The quadratic function stretches vertically by a factor of 2.

Step-by-step explanation:

There are many factors that play transformations in quadratic functions.

Let me give you some rules to help you with transformations.

We know that the standard form for a quad function is y= ax^2+bx+c.

We can write that in vertex form.

The formula is y=a(x-h)^2+k.

a, h, and k can contribute to factors on the graph.

Let's start with a.

When a is greater than 1, the graph stretches vertically, or it is just a stretch.

If a is less than 1 but greater than 0, the graph shrinks or compresses.

A also determines if you have a maximum or minimum as well as if the graph opens up or down.

With h, that plays a role with the horizontal translation.

No specific rules here, but here, the reason why it is one unit to the left and not one unit to the right is because of the formula.

remember how it is x-h. On a graph, it would be -1.

So x--1 is x+1.

Don't get fooled by this.

Vice versa as well.

With vertical translation, however, you do not need to remember anything. If it says -7 it is translated 7 units down from the parent function or y=x^2.

I hope this helps!

5 0

3 years ago

Suppose the time a child spends waiting at for the bus as a school bus stop is exponentially distributed with mean 7 minutes. De

Gala2k [10]

Answer:

The probability that the child must wait between 6 and 9 minutes on the bus stop on a given morning is 0.148.

Step-by-step explanation:

Let the random variable X represent the time a child spends waiting at for the bus as a school bus stop.

The random variable X is exponentially distributed with mean 7 minutes.

Then the parameter of the distribution is, $\lambda=\frac{1}{\mu}=\frac{1}{7}$ .

The probability density function of X is:

$f_{X}(x)=\lambda\cdot e^{-\lambda x};\ x>0,\ \lambda>0$

Compute the probability that the child must wait between 6 and 9 minutes on the bus stop on a given morning as follows:

$P(6\leq X\leq 9)=\int\limits^{9}_{6} {\lambda\cdot e^{-\lambda x}} \, dx$

$=\int\limits^{9}_{6} {\frac{1}{7}\cdot e^{-\frac{1}{7} \cdot x}} \, dx \\\\=\frac{1}{7}\cdot \int\limits^{9}_{6} {e^{-\frac{1}{7} \cdot x}} \, dx \\\\=[-e^{-\frac{1}{7} \cdot x}]^{9}_{6}\\\\=e^{-\frac{1}{7} \cdot 6}-e^{-\frac{1}{7} \cdot 9}\\\\=0.424373-0.276453\\\\=0.14792\\\\\approx 0.148$

Thus, the probability that the child must wait between 6 and 9 minutes on the bus stop on a given morning is 0.148.

6 0

3 years ago

What's 0.003 is 1/10 of what?

zvonat [6]

0.03 you just times it by ten or if its a decimal take away the 0 infront of it

7 0

3 years ago

Solve the system 2x+4y=16 5x +3y=19 then find the value of y/x

AURORKA [14]

Answer:

I would change 2x+4y=24 into x=12–2y

To do that, divide both sides by 2 and then subtract 2y on each side.

After that, substitute for x. 3x+2y=19 would become 3(12–2y)+2y=19.

Then solve.

3(12–2y)+2y=19

36–6y+2y=19

-4y+36=19

-4y=-17

y=4.25

Then, substitute y in either equation.

Either this:

3x+2y=19

3x+2(4.25)=19

3x+8.5=19

3x=10.5

x=3.5

Or:

2x+4y=24

2x+4(4.25)=24

2x+17=24

2x=7

x=3.5

Or you could solve it in the equation you created in the beginning:

x=12–2y

x=12–2(4.25)

x=12–8.5

x=3.5

The coordinates where the lines intercept are (3.5, 4.25).

Sorry for the long answer!

4 0

3 years ago

Help me out please :)

Alisiya [41]

Answer:

2$ I think

Step-by-step explanation:

8 0

3 years ago

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