How is estimation helpful when adding and subtracting decimals

2 answers:

6 0

It's helpful because let's say you have $3.23 and you need to give someone $1.00 then you would need to subtract then what way you will know what you need to do and how many money u have left

Gnesinka [82]2 years ago

4 0

Its a lot easier to do 1.200 - .200. Than to do 1.248- .239. How I see it, estimating always gives you something to fall back on or to help see if your exact answer is accurate

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Someone please help me with #28 and #30 I got myself super confused.

bogdanovich [222]

Question 28:

$S-2\pi r^2=2\pi rh$ Subtract $2\pi r^2$ on both sides

$\frac{S-2\pi r^2}{2\pi r} =h$ Divide $2\pi r$ on both sides

*(Answer)*= $\frac{S-2\pi r^2}{2\pi r} =h$

Question 30:

$a*t=v_{1}+v_{0}$ Multiply $t$ on both sides

$a*t+v_{0} =v_{1}$ Subtract $v_{0}$ on both sides

*(Answer)*= $a*t+v_{0} =v_{1}$

Hope This Helps

BangtanBoyScouts

4 0

3 years ago

ABCD is a rhombus, where m∠AED = 5x – 10. Use the properties of a rhombus to determine the value of x. Question 10 options: A) x

fomenos

Answer:

A) x = 20

Step-by-step explanation:

ABCD is a rhombus, AC and BD are diagonals which intersect each other at point E.

Since, diagonals of a rhombus are perpendicular bisector.

$\therefore \: m \angle AED = 90 \degree \\ \therefore \: (5x - 10) \degree = 90 \degree \\ \therefore \: 5x - 10 = 90 \\ \therefore \: 5x = 90 + 10 \\ \therefore \: 5x = 100 \\ \\ \therefore \: x = \frac{100}{5} \\ \\ \huge \red{ \boxed{ \therefore \: x =20}}$