Answer:
Thanks mate.
Step-by-step explanation:
Answer:
INF for first while D for second
Step-by-step explanation:
Ok I think I read that integral with lower limit 1 and upper limit infinity
where the integrand is ln(x)*x^2
integrate(ln(x)*x^2)
=x^3/3 *ln(x)- integrate(x^3/3 *1/x)
Let's simplify
=x^3/3 *ln(x)-integrate(x^2/3)
=x^3/3*ln(x)-1/3*x^3/3
=x^3/3* ln(x)-x^3/9+C
Now apply the limits of integration where z goes to infinity
[z^3/3*ln(z)-z^3/9]-[1^3/3*ln(1)-1^3/9]
[z^3/3*ln(z)-z^3/9]- (1/9)
focuse on the part involving z... for now
z^3/9[ 3ln(z)-1]
Both parts are getting positive large for positive large values of z
So the integral diverges to infinity (INF)
By the integral test... the sum also diverges (D)
Answer:
-40 °F = -40 °C
Step-by-step explanation:
(1) F = 1.8 C + 32
If the Fahrenheit and Celsius temperatures are the same, then
(2) F = C Substitute (2) into (1)
C = 1.8C + 32 Subtract 1.8 C from each side
C – 1.8 C = 32 Combine like terms
-0.8C = 32 Divide each side by -0.8
C = -32/0.8
(3) C = -40 Substitute (3) into (1)
F = 1.8(-40) + 32
F = -72 + 32
F = -40
So, -40 °F = -40 °C
The thermometer below shows that -40 °F = -40 °C.