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Zinaida [17]
3 years ago
11

Have to state if the triangles are similar or not.

Mathematics
1 answer:
scZoUnD [109]3 years ago
6 0

Answer:

Step-by-step explanation:

10). 1). Both the triangles are not similar.

     2). For the similarity of two triangles, corresponding sides of the triangles should be proportional and the included angles should be equal in measure.

         Although the angle given is equal but the corresponding sides of the triangles are not proportional, triangles are not similar.

          \frac{UW}{HF}= \frac{UV}{GF} (For similar triangles)

          \frac{9}{21}= \frac{18}{42}

          \frac{3}{7}=\frac{6}{7}

          But \frac{3}{7}\neq \frac{6}{7} therefore, both the triangles are not similar.

11). In ΔTUV and ΔCDE,

    If the given triangles are similar, their corresponding sides will be proportional and the included angle will be equal in measure.

    ∠C ≅ ∠T [Given]

    \frac{TU}{CD}= \frac{UV}{DE}

    \frac{30}{10}=\frac{27}{9}

    3 = 3

    True.

    Therefore, ΔTUV ~ ΔCDE (By SAS postulate of similarity]

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sometimes

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3 years ago
1 hour is equal to blank minutes
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A graph is made by a straight line that intersects the y axis at the point (0,12). Why isn't that graph a proportional relations
bogdanovich [222]

Answer:

The table of values and their graph show above a straight line that passes through the origin. This indicates that the relationship between the two currencies is in direct proportion. Think about what this means in real terms – if you have ten times more dollars than another person, when you both exchange your money, you will still have ten times more money. Notice also that the graph passes through the origin; this makes sense as if you have no dollars you will get no pounds!

We can express these relationships algebraically as well as graphically.

4 0
3 years ago
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6 0
3 years ago
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The attention span of children (ages 3 to 5) is claimed to be Normally distributed with a mean of 15 minutes and a standard devi
Agata [3.3K]

Answer:

If the observed sample mean is greater than 17.07 minutes, then we would reject the null hypothesis.

Step-by-step explanation:

We are given the following in the question:

Population mean, μ = 15 minutes

Sample size, n = 10

Alpha, α = 0.05

Population standard deviation, σ = 4 minutes

First, we design the null and the alternate hypothesis

H_{0}: \mu = 15\text{ minutes}\\H_A: \mu > 15\text{ minutes}

Since the population standard deviation is given, we use one-tailed z test to perform this hypothesis.

Formula:

z_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{\sigma}{\sqrt{n}} }

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Thus, we would reject the null hypothesis if the z-statistic is greater than this critical value.

Thus, we can write:

z_{stat} = \displaystyle\frac{\bar{x} - 15}{\frac{4}{\sqrt{10}} } > 1.64\\\\\bar{x} - 15>1.64\times \frac{4}{\sqrt{10}}\\\bar{x} - 15>2.07\\\bar{x} > 15+2.07\\\bar{x} > 17.07

Thus, the decision rule would be if the observed sample mean is greater than 17.07 minutes, then we would reject the null hypothesis.

6 0
3 years ago
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