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3 years ago

Need ASAP please!!!15 points! :)

Mathematics

1 answer:

ivanzaharov [21]3 years ago

4 0

Answer: expression below gives the average

rate of change of the function pon 5 sxs8?

08-5

1-10

8-5

07-1

8-5

Step-by-step explanation:

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Plz someone answer this with an explanation

worty [1.4K]

Answer:

1/3

Step-by-step explanation:

8 0

3 years ago

Which expression is equivalent to 4/9x7?

LiRa [457]

Is there an answer key?

8 0

3 years ago

The average of six numbers is 4. If the of two of those numbers is 2, what is the average of the other four numbers?

matrenka [14]

Answer:

Step-by-step explanation:

total sum of the 6 numbers

= 4 ×6

= 24

sum of numbers without the two 2s

= 24 - 2(2)

= 20

average of other 4 numbers

= 20 ÷ 4

= 5

6 0

3 years ago

How much is a one time investment of 250 be when invested at 6% for 40 years in compound annually

vova2212 [387]

6% increase is multiply by 1,06

done 40 times

so : 250* 1,06^40 = 2571 ,

7 0

2 years ago

In a cohort of 35 graduating students, there are three different prizes to be awarded. If no student can receive more than one p

sweet [91]

We have been given in a cohort of 35 graduating students, there are three different prizes to be awarded. We are asked that in how many different ways could the prizes be awarded, if no student can receive more than one prize.

To solve this problem we will use permutations.

$_{r}^{n}\textrm{P}={_{3}^{35}\textrm{P}}$

We know that formula for permutations is given as

$_{r}^{n}\textrm{P}=\frac{n!}{(n-r)!}$

On substituting the given values in the formula we get,

${_{3}^{35}\textrm{P}}=\frac{35!}{(35-3)!}=\frac{35!}{32!}$

$=\frac{35\cdot 34\cdot 33\cdot 32!}{32!}\\
\\
=35\cdot 34\cdot 33=39270$

Therefore, there are 39270 ways in which prizes can be awarded.

6 0

3 years ago