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Vsevolod [243]
3 years ago
10

Find two prime numbers between 30 and 45.

Mathematics
2 answers:
timofeeve [1]3 years ago
8 0

Answer: PRIME NUMBERS BETWEEN 30 AND 45 ARE 31, 37, 41, and 43.

prohojiy [21]3 years ago
6 0
The prime numbers between 30 and 45 are 31, 37, 41, and 43
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Calculate the volume of each geometric shape:
pav-90 [236]

Answer:

a) 235.62in³

b) 904.78in³

Step-by-step explanation:

a) The formula to find the volume of a cylinder is:

V = \pi r^2h

We are given that r = 5 and h = 3, so we can just plug in and solve:

V = \pi(5)^2(3) = 235.62in^3

b) The formula to find the volume of a sphere is:

V = \frac{4}{3}\pi r^3

We are given that the diameter is 12in, which means that the radius (r) must be 6in (half the diameter). Now, we can plug in and solve:

V = \frac{4}{3}\pi (6)^3 = 904.78in^3

5 0
3 years ago
What is the best choice for value y?
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Answer:The answer is second option

{x}^{10 - 3}  \\  {x}^{7}

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balandron [24]

Answer:I think it might be B,C,A,D

Step-by-step explanation:

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3 years ago
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If x degree and 115 degree are co exterior angles find the vaule of x degree
Lesechka [4]

Answer:

65 degrees

Step-by-step explanation:

An exterior angle form a linear pair with an interior angle.

A linear pair of angles must add up to 180 degrees

180-115 = 65

3 0
3 years ago
I need to find the missing numbers
const2013 [10]

Answer:

b11 = -14

b12 = 9

b13 = 8

Step-by-step explanation:

* Lets revise some notes to solve the problem

- Any matrix has a dimension m × n, where m is the number of rows

 and n the number of columns

- We can add matrices with same dimensions

* Now lets solve the problem

∵ B+\left[\begin{array}{ccc}15&-7&4\\0&1&2\end{array}\right]=\left[\begin{array}{ccc}1&2&12\\4&0&2\end{array}\right]

- Let B=\left[\begin{array}{ccc}b11&b12&b13\\b21&b22&b23\end{array}\right]

∴ \left[\begin{array}{ccc}b11&b12&b13\\b21&b22&b23\end{array}\right]+\left[\begin{array}{ccc}15&-7&4\\0&1&2\end{array}\right]=\left[\begin{array}{ccc}1&2&12\\4&0&2\end{array}\right]

- Lets add and find the missing

* Lets start with the first rows

∵ b11 + 15 = 1 ⇒ subtract 15 from both sides

∴ b11 = -14

∵ b12 + -7 = 2 ⇒ add 7 to both sides

∴ b12 = 9

∵ b13 + 4 = 12 ⇒ subtract 4 from both sides

∴ b13 = 8

* Now lets start with the second rows

∵ b21 + 0 = 4

∴ b21 = 4 ⇒ given

∵ b22 + 1 = 0 ⇒ subtract 1 from both sides

∴ b22 = -1 ⇒ given

∵ b23 + 2 = 2 ⇒ subtract 2 from both sides

∴ b23 = 0 ⇒ given

5 0
3 years ago
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