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yarga [219]
2 years ago
10

Can anyone help me please thank you if you do

Mathematics
1 answer:
omeli [17]2 years ago
6 0

Hai!

Your answer should be A.

So so sorry if I am Wrong.

Have a good day! :3

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PLEASE HELP!!! I do not understand!!!
sladkih [1.3K]

Answer:

110 + 5x (I'm not sure if you need the dollar signs...if you do, one goes in front of the 110 and one goes in front of the 5)

Step-by-step explanation:

$20 + $90 = $110

<u><em>Equation:</em></u>

110 + 5x

110 represents the base cost of the turtle and the terrarium.

5 represents the cost of the turtle food

x represents the number of weeks that she is purchasing the food.

4 0
3 years ago
Urgent help algebra 2
Rudiy27
Slope-intercept you have right:
y=3/4x-7

Point slope form is:
y − y1 = m(x − x1)

so

y +7 = 3/4(x -0)

or

y + 7 = 3/4x
6 0
1 year ago
What is b1 and r of geometrical sequence if b3 −b1 = 16 and b5 −b3 = 144.
Naily [24]

Answer:

b1 = 2 ; r = 3

Step-by-step explanation:

Given that :

if b3 −b1 = 16 and b5 −b3 = 144.

For a geometric series :

Ist term = a

Second term = ar

3rd term = ar^2

4th term = ar^3

5th term = ar^4 ;...

If b3 - b1 = 16;

ar^2 - a = 16

a(r^2 - 1) = 16 - - - (1)

b5 - b3 = 144

ar^4 - ar^2 = 144

ar^2(r^2 - 1) = 144 - - - - (2)

Divide (1) by (2)

a(r^2 - 1) / ar^2(r^2 - 1) = 16 /144

a / ar^2 = 1 / 9

ar^2 = 9a

Substitute for a in ar^2 - a = 16

9a - a = 16

8a = 16

a = 2

From ar^2 - a = 16

2r^2 - 2 = 16

2r^2 = 16 + 2

2r^2 = 18

r^2 = 18 / 2

r^2 = 9

r = √9

r = 3

Hence ;

a = b1 = 2 ; r = 3

7 0
3 years ago
2m+4/8=w solve for m
Kisachek [45]

Answer: m=w/2-1/4

Step-by-step explanation: In the picture

8 0
3 years ago
B. Determine the values of a and b so that f is continuous.<br><br> Please help!
wlad13 [49]

Answer:

following are the solution to this question:

Step-by-step explanation:

Please find the complete question in the attached file.

\lim_{x\to 2}+f(x) = \lim_{x\to 2}+ (ax^2-bx+3) = 4a-2b+3\\\\ \to  4a-2b+3 = 4\\\\  \therefore \ \ 4a-2b = 1\\\\

The one-sided limits of F(x) at x = 3 must be equivalent for f(x) to be continuous at x = 3.

\to \lim_{x\to 3}- f(x) = \lim_{x\to 3}- (ax^2-bx+3) = 9a-3b+3\\\\ \to \lim_{x\to 3}+ f(x) = \lim_{x\to 3}+ (2x-a+b) = 6-a+b\\\\  

So,

\to 9a-3b+3 = 6-a+b\\\\\therefore\\ \to 10a -4b = 3

\to 4a - 2b = 1......(a)\\\to 10a - 4b = 3.......(b)\\

In equation a multiply the by -2 and then add in the equation b:

\to -8a + 4b = -2\\\to 10a - 4b = 3\\ \to 2a = 1\\\\ \to   a = \frac{1}{2}\\\\ \to \ 4(\frac{1}{2}) - 2b = 1\\\\ \to 2 - 2b = 1\\\\ \to   -2b = -1\\\\ \to b = \frac{1}{2}  

So, the value of a \ and \ b= \frac{1}{2}

4 0
2 years ago
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