Answer:
<h3><u>Mean</u></h3>
<u />
![\textsf{Mean}\:\overline{X}=\sf \dfrac{\textsf{sum of all the data values}}{\textsf{total number of data values}}](https://tex.z-dn.net/?f=%5Ctextsf%7BMean%7D%5C%3A%5Coverline%7BX%7D%3D%5Csf%20%5Cdfrac%7B%5Ctextsf%7Bsum%20of%20all%20the%20data%20values%7D%7D%7B%5Ctextsf%7Btotal%20number%20of%20data%20values%7D%7D)
![\implies \sf Mean\:(Nilo)=\dfrac{5+6+14+15}{4}=\dfrac{40}{4}=10](https://tex.z-dn.net/?f=%5Cimplies%20%5Csf%20Mean%5C%3A%28Nilo%29%3D%5Cdfrac%7B5%2B6%2B14%2B15%7D%7B4%7D%3D%5Cdfrac%7B40%7D%7B4%7D%3D10)
![\implies \sf Mean\:(Lisa)=\dfrac{8+9+11+12}{4}=\dfrac{40}{4}=10](https://tex.z-dn.net/?f=%5Cimplies%20%5Csf%20Mean%5C%3A%28Lisa%29%3D%5Cdfrac%7B8%2B9%2B11%2B12%7D%7B4%7D%3D%5Cdfrac%7B40%7D%7B4%7D%3D10)
<h3><u>Standard Deviation</u></h3>
![\displaystyle \textsf{Standard Deviation }s=\sqrt{\dfrac{\sum X^2-\dfrac{(\sum X)^2}{n}}{n-1}}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Ctextsf%7BStandard%20Deviation%20%7Ds%3D%5Csqrt%7B%5Cdfrac%7B%5Csum%20X%5E2-%5Cdfrac%7B%28%5Csum%20X%29%5E2%7D%7Bn%7D%7D%7Bn-1%7D%7D)
![\begin{aligned}\displaystyle \textsf{Standard Deviation (Nilo)} & =\sqrt{\dfrac{(5^2+6^2+14^2+15^2)-\dfrac{(5+6+14+15)^2}{4}}{4-1}}\\\\& = \sqrt{\dfrac{482-\dfrac{40^2}{4}}{3}}\\\\& = \sqrt{\dfrac{82}{3}}\\\\& = 5.23\end{aligned}](https://tex.z-dn.net/?f=%5Cbegin%7Baligned%7D%5Cdisplaystyle%20%5Ctextsf%7BStandard%20Deviation%20%28Nilo%29%7D%20%26%20%3D%5Csqrt%7B%5Cdfrac%7B%285%5E2%2B6%5E2%2B14%5E2%2B15%5E2%29-%5Cdfrac%7B%285%2B6%2B14%2B15%29%5E2%7D%7B4%7D%7D%7B4-1%7D%7D%5C%5C%5C%5C%26%20%3D%20%5Csqrt%7B%5Cdfrac%7B482-%5Cdfrac%7B40%5E2%7D%7B4%7D%7D%7B3%7D%7D%5C%5C%5C%5C%26%20%3D%20%5Csqrt%7B%5Cdfrac%7B82%7D%7B3%7D%7D%5C%5C%5C%5C%26%20%3D%205.23%5Cend%7Baligned%7D)
![\begin{aligned}\displaystyle \textsf{Standard Deviation (Lisa)} & =\sqrt{\dfrac{(8^2+9^2+11^2+12^2)-\dfrac{(8+9+11+12)^2}{4}}{4-1}}\\\\& = \sqrt{\dfrac{410-\dfrac{40^2}{4}}{3}}\\\\& = \sqrt{\dfrac{10}{3}}\\\\& = 1.83\end{aligned}](https://tex.z-dn.net/?f=%5Cbegin%7Baligned%7D%5Cdisplaystyle%20%5Ctextsf%7BStandard%20Deviation%20%28Lisa%29%7D%20%26%20%3D%5Csqrt%7B%5Cdfrac%7B%288%5E2%2B9%5E2%2B11%5E2%2B12%5E2%29-%5Cdfrac%7B%288%2B9%2B11%2B12%29%5E2%7D%7B4%7D%7D%7B4-1%7D%7D%5C%5C%5C%5C%26%20%3D%20%5Csqrt%7B%5Cdfrac%7B410-%5Cdfrac%7B40%5E2%7D%7B4%7D%7D%7B3%7D%7D%5C%5C%5C%5C%26%20%3D%20%5Csqrt%7B%5Cdfrac%7B10%7D%7B3%7D%7D%5C%5C%5C%5C%26%20%3D%201.83%5Cend%7Baligned%7D)
<h3><u>Summary</u></h3>
Nilo has a mean score of 10 and a standard deviation of 5.23.
Lisa has a mean score of 10 and a standard deviation of 1.83.
The <u>mean</u> scores are the <u>same</u>.
Nilo's standard deviation is higher than Lisa's. Therefore, Nilo's test scores are more <u>spread out</u> that Lisa's, which means Lisa's test scores are more <u>consistent</u>.
Answer:
41.0704225352 or 284x/9 + 0
Step-by-step explanation:
Hello!
First of all let's divide and find how much each calculator cost.
95.2/14=$6.80
Now we will subtract from 24.
24-6.8= 17.2
Mr. Morris has $17.2 left to spend on each student.
I hope this helps!