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GrogVix [38]
3 years ago
12

Is the relationship linear, exponential, or neither?

Mathematics
1 answer:
Natali5045456 [20]3 years ago
3 0

Answer:

linear

Step-by-step explanation:

the values are changing at a constant rate so it is a linear relationship

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Just take the points..!​
xenn [34]
Hello thanks hope you have a good day!
3 0
3 years ago
3. Students arrive at an ATM machine in a random pattern with an average inter-arrival time of 3 minutes. The length of transact
svp [43]

Answer:

The probability that a student arriving at the ATM will have to wait is 67%.

Step-by-step explanation:

This can be solved using the queueing theory models.

We have a mean rate of arrival of:

\lambda=1/3\,min^{-1}

We have a service rate of:

\mu=1/2\,min^{-1}

The probability that a student arriving at the ATM will have to wait is equal to 1 minus the probability of having 0 students in the ATM (idle ATM).

Then, the probability that a student arriving at the ATM will have to wait is equal to the utilization rate of the ATM.

The last can be calculated as:

P_{n>0}=\rho=\dfrac{\lambda}{\mu}=\dfrac{1/3}{1/2}=\dfrac{2}{3}=0.67

Then, the probability that a student arriving at the ATM will have to wait is 67%.

4 0
4 years ago
Falls City has a current population of 3,300 and is increasing 4.1% every year. How large will the population be in 8 years? Rou
OverLord2011 [107]
4382


Since 4.1% x 8 = 32.8%

32.8% of 3300 = 1082.4

3300 + 1082.4 = 4082 rounded
3 0
3 years ago
Chang runs 7 miles in 60 minutes. At the same rate, how many miles would he run in 24 minutes.
PSYCHO15rus [73]
2.8 miles.

My Work/Reasoning:
First we find the rate. 7/60 mpm (miles per minutes)
Then we multiply that by 24. 7/60 * 24
Finally, we solve the equation and learn that Chang would run 2.8 miles in 24 minutes.
7 0
4 years ago
Read 2 more answers
Match the independent variable, dependent variable and constant for the following statement.
den301095 [7]
Independent: cell phone plan
dependent: monthly cost
constant: per month/per minute (money)
5 0
4 years ago
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