Answer:
the statement is false
Step-by-step explanation:
Answer:
The correct answer is "
". A further solution is provided below.
Step-by-step explanation:
According to the question,
The probability of getting a 5 will be:
= 
= 
The probability of getting a 7 will be:
= 
= 
The probability of not a 5 nor a 7 will be:
= ![1-[\frac{4}{36} +\frac{4}{36} ]](https://tex.z-dn.net/?f=1-%5B%5Cfrac%7B4%7D%7B36%7D%20%2B%5Cfrac%7B4%7D%7B36%7D%20%5D)
= 
= 
Now,
For roll of 2 dice,
⇒ 
![=\frac{1}{9} [1+\frac{13}{18} +\frac{13^2}{18^2} +\frac{13^3}{18^3} +...]](https://tex.z-dn.net/?f=%3D%5Cfrac%7B1%7D%7B9%7D%20%5B1%2B%5Cfrac%7B13%7D%7B18%7D%20%2B%5Cfrac%7B13%5E2%7D%7B18%5E2%7D%20%2B%5Cfrac%7B13%5E3%7D%7B18%5E3%7D%20%2B...%5D)
![=\frac{1}{9} [\frac{1}{1-\frac{13}{18} } ]](https://tex.z-dn.net/?f=%3D%5Cfrac%7B1%7D%7B9%7D%20%5B%5Cfrac%7B1%7D%7B1-%5Cfrac%7B13%7D%7B18%7D%20%7D%20%5D)
![=\frac{1}{9} [{\frac{1}{\frac{5}{8} } ]](https://tex.z-dn.net/?f=%3D%5Cfrac%7B1%7D%7B9%7D%20%5B%7B%5Cfrac%7B1%7D%7B%5Cfrac%7B5%7D%7B8%7D%20%7D%20%5D)
Answer:
40.036 is your answer.
You can start by adding 33 + 7 which equals to 40.
So you have 44.00
Now since the 3 in 7.03 is 2 jumps behind the point. You would put the 3 2 behind the point.
Leave the 6 and the 0. Make the 3 in front of the 6.
Your number should be 40.036
Tell me if you want me to explain it more.
Please mark me brainless
Answer:
c
Step-by-step explanation:
