The answer is 0.4%. The probability that a unit end in a rework can be calculated using the following equation:
P(rework)= P(defects found) * P(defect)
= .8 * .005
= .004
= 0.4%
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Answer:
4
Step-by-step explanation:
2L=w
32=LxW
so you put the 2L as the w
which is 32=Lx2L
32=2L^2
16=L^2
4=L
*To find the width you input 4 as L*
So 8=W
The shortest side would be 4
hi
if x= 2+4y-5 then x-2 +5 = 4y so y = (x-2+5) /4 = ( x+3) /4
conclusion y = (x+3)/4
