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RSB [31]
3 years ago
12

Write any three rational number between -3 and 0

Mathematics
1 answer:
ella [17]3 years ago
8 0

Answer:

negative square root of 2

negative square root of 3

negative square root of 5

Step-by-step explanation:

:)

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8 mi. 133 yd. 2 ft. – 5 mi. 107 yd. 2 ft.
Murrr4er [49]

8 mi. 133 yd. 2 ft. - 5mi. 107 yd. 2 ft.

= (8 mi. - 5 mi.) + (133 yd. - 107 yd) + (2 ft. - 2ft.)

= 3 mi. +26 yd.

<h3>= 3 mi. 26 yd.</h3>
8 0
3 years ago
Evaluate the following functions at x = 10 q(x)=x^2-2x+2​
Oduvanchick [21]

Answer:

82

Step-by-step explanation:

given:x=10

Evaluating,

(10)²-2(10)+2

=100-20+2

=80+2

=82

Pls mark me brainliest

5 0
3 years ago
Sharon manages the Spirit Supply store at Lakefield Middle School. She tracks the sale of various items in her inventory so that
Airida [17]
Here is a graph. I hope it helped :)

7 0
3 years ago
Can i please get the answer to number 6 ?
IrinaVladis [17]
A full circle in radians is 2π, and in degrees it's 360°. I want to convert the 72° to radians:

72° in radians = 72/360 * 2π = 2/5π

The circumference of a full circle is the number of radians times the radius. (ie., 2πr), so the JK part of the circle is:

5* 2/5π simplifies to 2π
6 0
3 years ago
Many people use scanners to read documents and store them into pdf file. To help determine which brand of scanner to buy, a stud
konstantin123 [22]

The data is missing in the question. The data is provided below :

Document : 1     2      3      4      5     6      7      8

Brand A       17  29    18    14    21   25    22    29

Brand B       21  38    15    19    22   30    31   37

Solution :

State of the hypothesis of the null hypothesis and alternate hypothesis.

Null hypothesis : $h_A = h_B$

Alternate hypothesis : $h_A > h_B$

These hypothesis is a one tailed test. The null hypothesis will get rejected when the mean difference between the sample means is very small.

Significance level = 0.05

Therefore the standard error is :  $SE = \sqrt{(\frac{s^2_1}{n_1})+(\frac{s^2_2}{n_2})}$

                                                         = 3.602

And the degree of freedom, DF = 14

$t=\frac{(x_1-x_2)-d}{SE}$

 = -1.319

Here, $s_1$ = standard deviation of the sample 1

        $s_2$ = standard deviation of the sample 2

         $n_1$ = size of the sample 1

        $n_2$ = size of the sample 2

         $x_1$ = mean of the sample 1

        $x_2$ = mean of the sample 2      

          d = the hypothesis difference between the population mean

The observed difference in a sample means t static of -1.32. From t distribution calculator to determine P($t \leq -1.32$) = 0.1042  

Since the P value of 0.1042 is greater than significance level o 0.05, we therefore cannot reject the null hypothesis.

But from the test, we have no sufficient evidence that supports that Brand A is better than Brand B.      

8 0
3 years ago
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