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vredina [299]
3 years ago
12

Hep with this please

Mathematics
1 answer:
pishuonlain [190]3 years ago
6 0

Answer:

x = 23

Step-by-step explanation:

6x+19+x = 180

7x = 180 - 19

7x =  161

x = 161/7

x = 23

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What is radius???????
xz_007 [3.2K]

A radius of a circle or sphere is any of the line segments from its center to its perimeter, and in more modern usage, it is also their length. Set up the formula for the area of a circle. The formula is A = π r 2 it equals the area of the circle, and r equals the radius.

Solve for the radius.

Plug the area into the formula.

Divide the area by.

Take the square root.

8 0
3 years ago
1. Find the area of the triangle with the given measurements. Round the solution to the nearest hundredth if necessary.
gtnhenbr [62]
1. First, we are going to draw our triangle (picture 1). Next, we are going to use the cosine rule to find the length of side b:
b^2=a^2+c^2-2accosA
b= \sqrt{a^2+c^2-2accosA}
b= \sqrt{14^2+20^2-2(14)(20)cos(74)}
b=21.02
Now that we have all the sides of the triangle, we use Heron's formula to find its area. But first we need to find the semi-perimeter of the triangle. To do it, we are going to use the formula: s= \frac{a+b+c}{2}
where 
s is the semi-perimeter.
a, b, and c are the sides of the triangle. 

s= \frac{14+21.02+20}{2}
s= \frac{54.02}{2}
s=27.51

Now, we can use Heron's formula: A= \sqrt{s(s-a)(s-b)(s-c)}
where
A is the area of the triangle.
s is the semi-perimeter of the triangle.
a, b, and c are the sides of the triangle.
A= \sqrt{27.51(27.51-14)(27.51-21.02)(27.51-20}
A=134.59cm^2

The area of the triangle ABC is 134.59 square centimeters. We can conclude that the correct answer of your given choices is: 134.58 cm2 (your teacher made a little rounding error)

2. Just like before, the first thing we are going to do is draw the triangle (picture 2). Next, we are going to use the cosine rule to find the length of side b:
b= \sqrt{a^2+c^2-2accosA}
b= \sqrt{11^2+18^2-2(11)(18)cos(71)}
b=17.78

Semi-perimeter:
s= \frac{a+b+c}{2}
s= \frac{11+17.78+18}{2}
s=23.39

Heron's formula:
A= \sqrt{s(s-a)(s-b)(s-c)}
A= \sqrt{23.39(23.39-11)(23.39-17.78)(23.39-18)}
A=93.61cm^2

The area of triangle ABC is 93.61 square centimeters. We can conclude that the correct answer is <span>93.61 cm2

3. We have the vectors </span><span>P = (-5, 5) and Q = (-13, 6), and we want to find the vector 2 times PQ; in other words, we want to find the result of the multiplication between the vector initiating at P and ending at Q and the scalar 2.
First we are going to find the components of the vector </span>P and ending at Q:
PQ=\ \textless \ -13-(-5), 6-5\ \textgreater \
PQ=\ \textless \ -13+5, 1\ \textgreater \
PQ=\ \textless \ -8,1\ \textgreater \

Next, we are going to multiply the vector by the scalar 2:
2PQ=2\ \textless \ -8,1\ \textgreater \
2PQ=\ \textless \ -16,2\ \textgreater \

Now, we can find the magnitude of the vector. Remember that the magnitude of a vector is given by the Pythagorean theorem: |a|= \sqrt{x^2+y^2}
where
|a| is the magnitude of the vector 
\ \textless \ x,y\ \textgreater \ are the components of the vector.

We know that the components of the vector are x=-16 and y=2, so lets replace those vales in our equation: 
|2PQ|= \sqrt{-16^2+2^2}
|2PQ|= \sqrt{-16^2+2^2}
|2PQ|= \sqrt{256+4}
|2PQ|= \sqrt{260}

We can conclude that the correct answer is: <span><-16, 2>, square root of two hundred and sixty.</span><span>
</span>

4 0
4 years ago
How to solve this problem
Kamila [148]
First you to eliminate i from denominator.
mult by (7+3i) above and below
=(49+42i-9)/(49-9)
which is (40+42i)/40 which can simplify
4 0
3 years ago
PLEASE HELP me with this!! will mark brainliest.
e-lub [12.9K]

Answer:

4 roots

Explain:

Odd degree polynmial

3 0
3 years ago
Please Help me!!!!!!
Zigmanuir [339]

Answer:

it's A i just took the test

8 0
3 years ago
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