The total area of pool and border = 361 square feet.
Length of square pool = x
Length of square pool plus border = (x + 1 +1 ) = x + 2
There is 1 foot length on each side on the x length.
The other length of the square pool and border = (x + 2)
Area = (x+2)(x+2)
(x + 2)(x +2) = 361. Let A = x +2
A*A = 361
A² = 361 Take square root of both sides
A = √361
A = 19
A = x + 2 = 19
x = 19 - 2
x = 17
Area of square pool = x*x = 17*17 = 289
Area of the pool = 289 square feet.
Answer:
An example would be
(x+3)-(y+12)
The two constants are 3 and 12 (I'm assuming you meant "constant" as in the number that stands by itself and not "constatant" lol)
The two variables are x and y
The two operations are addition and subtraction
In words you could say "the quantity of x plus three minus the quantity of y plus twelve"
Answer:
WHat do we help with?
Step-by-step explanation:
Answer:
1) y = -2x - 1
2) y = -3/4 + 3
3) y = 4x + 9
4) y = - 5/3x - 2
Step-by-step explanation:
b = y - m*x
1) (-7,13) and slope: -2
b = 13 - (-2)*(-7)
b = 13 - 14
b = -1
2) (4,6) lope = -3/4
b = 6 - (-3/4)*(-4)
b = 6 - 3
b = 3
y = -3/4x + 3
3) (-5,-11) and (3,-7)
Slope: (1 - - 11)/(-2 - - 5) = 12/3
= 4
b = -11 - (4) (-5) = 9
b = 9
4) slope = (-7 - 8)/(3- - 6)
= -15/9 = - 5/3
b = 8 - (-5/3)*(-6)
b = 8 - 10
b = -2