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2 years ago

Write the following relation as a linear equation in standard form. Include a space between terms and operations.

Mathematics

1 answer:

kow [346]2 years ago

4 0

Answer:

In the form of

Y= mx+c

Y= 1/2x +2

m = 1/2

Step-by-step explanation:

A linear equation in it's standard form is in the format

Y= mx+c

Where m is the slope and c is the y intercept

Let's use these two points to determine both the slope and the equation

(2, 3), (4,4)

Slope= (y2-y1)/(x2-x1)

Slope= (4-3)/(4-2)

Slope= 1/2

Equation of the linear function

(Y-y1)/(x-x1)= m

(Y-3)/(x-2)= 1/2

2(y-3) = x-2

2y -6 = x-2

2y= x-2+6

2y= x+4

Y= 1/2x +2

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Step-by-step explanation:

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Suppose we take the interval [−5,7] and divide it into 4 equal subintervals. Find the width Δn of each subinterval. Δn = If we n

lana66690 [7]

Answer:

$x_0=-5\\x_1=-2\\x_2=1\\x_3=4\\x_4=7$

Δn=3

Step-by-step explanation:

Remember, if we need to divide the interval (a,b) in n equal subinterval, then we need divide the distance (d) between the endpoints of the interval and divide it by n. Then the width Δn of each subinterval is d/n.

We have the interval [-5,7]. The distance between the endpoints of the interval is

$d=7-(-5)=12$ .

Now, we divide d by 4 and obtain $\frac{d}{4}=\frac{12}{4}=3$

Then, Δn=3.

Now, to find the endpoints of each sub-interval, we add 3 from the left end of the interval.

$-5=x_0\\x_0+3=-5+3=-2=x_1\\x_1+3=1=x_2\\x_2+3=4=x_3\\x_3+3=7=x_4$

So,

$x_0=-5\\x_1=-2\\x_2=1\\x_3=4\\x_4=7$

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3 years ago