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kumpel [21]
3 years ago
8

Write the following relation as a linear equation in standard form. Include a space between terms and operations.

Mathematics
1 answer:
kow [346]3 years ago
4 0

Answer:

In the form of

Y= mx+c

Y= 1/2x +2

m = 1/2

Step-by-step explanation:

A linear equation in it's standard form is in the format

Y= mx+c

Where m is the slope and c is the y intercept

Let's use these two points to determine both the slope and the equation

(2, 3), (4,4)

Slope= (y2-y1)/(x2-x1)

Slope= (4-3)/(4-2)

Slope= 1/2

Equation of the linear function

(Y-y1)/(x-x1)= m

(Y-3)/(x-2)= 1/2

2(y-3) = x-2

2y -6 = x-2

2y= x-2+6

2y= x+4

Y= 1/2x +2

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Identify the k-value that makes the relationship shown in the table below proportional.​
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Answer:

The value of k that makes the relationship shown in the table below proportional is \mathbf{\frac{1}{2}}

Step-by-step explanation:

The relation is proportional if y=kx \:or\:k=\frac{y}{x}

Putting values of x and y to find k.

For x =2 and y =1 k is: k=\frac{y}{x}=\frac{1}{2}

For x =4 and y =2 k is: k=\frac{y}{x}=\frac{2}{4} =\frac{1}{2}

For x =6 and y = 3 k is: k=\frac{y}{x}=\frac{3}{6} =\frac{1}{2}

For x = 8 and y = 4 k is: k=\frac{y}{x}=\frac{4}{8} =\frac{1}{2}

For x =10 and y = 5 k is: k=\frac{y}{x}=\frac{5}{10} =\frac{1}{2}

So, The value of k that makes the relationship shown in the table below proportional is \mathbf{\frac{1}{2}}

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3 years ago
Point F is located on the coordinate grid at (-8.35, -2.14). In which quadrant is Point F located?
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Step-by-step explanation:

:) ------------------

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Step-by-step explanation:

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If x-1/3 = k and k = 3, what is the value of x ?<br> A) 2<br> B) 4<br> C) 9<br> D) 10
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Answer:

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Step-by-step explanation:

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We know that k=3, so we can substitute that into the equation

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