Write the following relation as a linear equation in standard form. Include a space between terms and operations.

Mathematics

1 answer:

kow [346]3 years ago

4 0

Answer:

In the form of

Y= mx+c

Y= 1/2x +2

m = 1/2

Step-by-step explanation:

A linear equation in it's standard form is in the format

Y= mx+c

Where m is the slope and c is the y intercept

Let's use these two points to determine both the slope and the equation

(2, 3), (4,4)

Slope= (y2-y1)/(x2-x1)

Slope= (4-3)/(4-2)

Slope= 1/2

Equation of the linear function

(Y-y1)/(x-x1)= m

(Y-3)/(x-2)= 1/2

2(y-3) = x-2

2y -6 = x-2

2y= x-2+6

2y= x+4

Y= 1/2x +2

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How do i solve functions?

Maksim231197 [3]

Most quadratic functions(which is what you have there, to a degree of 2) are solved using factoring and the zero product law. If you can not factor then you have to use the quadratic formula or graph it. However this one can be factored.
It's pretty simple to just factor it by inspection but I use the chart method, if you know decomposition that works as well.
Factoring gives us,
$(2x + 1)(x - 3) = 0$
Then you set each factor to 0 and solve for x,
$2x + 1 = 0$
$2x = - 1$
$x = \frac{ - 1}{2}$
And the second one,
$x - 3 = 0$
$x = 3$
The solutions to this equation are
x = -1/2, 3

6 0

3 years ago

The temperature has been going down at a constant rate.In 4 hours it went down 12 degrees.Which expression best shows the temper

fomenos

Answer:

t = t₀ - 3n

Step-by-step explanation:

Let t be the temperature and t₀ be the initial temperature of the day

Let n be the number of hours after the initial temperature ( t₀) was registered

Let -3 be the constant of change of temperature ( In 4 hours it went down 12 degrees)

Now, let's write down the expression that shows the temperature change each hour, this way:

t = t₀ - 3n