Y=12/x
12/2=6
12/4=3
12/8=1.5 or 3/2
12/12=1
Answer is b
Steps in multiplying fractions. Remember: finding common denominator is not necessary in multiplying fractions.
Common denominators are only needed in adding and subtracting fractions.
14/15 * 5/2
Step 1. Multiply the numerators.
14 * 5 = 70
Step 2. Multiply the denominators
15 * 2 = 30
Step 3. Simplify the fraction.
70/30 = 2 10/30 = 2 1/3
*the fraction 10/30 can still be simplified by dividing both numbers by 10. Hence, 1/3.
Steps in Dividing fractions.
24/60 ÷ 8/15
Step 1. Get the reciprocal of the 2nd fraction. Reciprocal means the reverse of the fraction. Simply swap the places of the numbers.
Reciprocal of 8/15 is 15/8.
Step 2. Multiply the 1st fraction to the reciprocal of the 2nd fraction. Follow steps in multiplying fractions.
24/60 * 15/8 = (24*15) / (60*8) = 360/480
Step 3. Simplify the fraction.
360/480 = 9 / 12 = 3/4
360 ÷ 40 = 9 ; 9 ÷ 3 = 3
480 ÷ 40 = 12 ; 12 ÷ 3 = 4
Answer:
-2, -5
Step-by-step explanation:
h2 + 7h + 10 = 0
h^2 +7h + 10 = 0
h^2 +2h +5h + 10 = 0
h(h+2) + 5(h+2) = 0
h+2 = 0 or h+5 = 0
h = -2 or h = -5
80,000 per year....there are 12 months in a year
80,000 / 12 = 6666.67 per month
Answer:
Let X the random variable that represent the heights of a population, and for this case we know the distribution for X is given by:
Where
and
Since the distribution for X is normal then the we know that the distribution for the sample mean
is given by:
And the standard error is given by:

Step-by-step explanation:
Previous concepts
Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".
The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".
Solution to the problem
Let X the random variable that represent the heights of a population, and for this case we know the distribution for X is given by:
Where
and
Since the distribution for X is normal then the we know that the distribution for the sample mean
is given by:
And the standard error is given by:
