Domain<span>: The set of all possible input values (commonly the "x" variable) It is the set of all real numbers for which a function is mathematically defined.
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![f(x) = \sqrt[1]{x-9}](https://tex.z-dn.net/?f=f%28x%29%20%3D%20%20%5Csqrt%5B1%5D%7Bx-9%7D%20)
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The function has noun defined points nor domain constraints. Therefore, the domain is
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Answer:
ST = 4
Step-by-step explanation:
A segment joining the midpoints of 2 sides of a triangle is half the length of the third side.
ST = 
PQ substitute values
- 32 + 9x = (- 5x + 28) ← multiply both sides by 2 to clear the fraction
- 64 + 18x = - 5x + 28 (add 5x to both sides )
- 64 + 23x = 28 ( add 64 to both sides )
23x = 92 ( divide both sides by 23 )
x = 4
Then
ST = - 32 + 9x = - 32 + 9(4) = - 32 + 36 = 4
Answer: P(B|G) = 3/5 = 0.6
the probability that the guest is the friend of bride, P(bride | groom) is 0.6
Complete Question:
The usher at a wedding asked each of the 80 guests whether they werea friend of the bride or of the groom. The results are: 59 for Bride, 50 for Groom, 30 for both. Given that the randomly chosen guest is the friend of groom, what is the probability that the guest is the friend of bride, P (bride | groom)
Step-by-step explanation:
The conditional probability P(B|G), which is the probability that a guest selected at random who is a friend of the groom is a friend of the bride can be written as;
P(B|G) = P(B∩G)/P(G)
P(G) the probability that a guest selected at random is a friend of the groom.
P(G) = number of groom's friends/total number of guests sample
P(G) = 50/80
P(B∩G) = the probability that a guest selected at random is a friend is a friend of both the bride and the groom.
P(B∩G) = number of guests that are friends of both/total number of sample guest
P(B∩G) = 30/80
Therefore,
P(B|G) = (30/80)/(50/80) = 30/50
P(B|G) = 3/5 = 0.6
Answer:
A
Step-by-step explanation:
I linked a drawing below
Rectangle ABCD-Purple
Rectangle A'B'C'D'- Turquoise/Blue
Rectangle A''B''C''D''- Maroon/Red
Answer:
Yes, the sides form a right triangle.
Step-by-step explanation:
<u>Pythagorean Theorem:</u>
a² + b² = c²
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20² + 21² = 29²
║a² = 20² = 400
║b² = 21² = 441
║c² = 29² = 841
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400 + 441 = 841
║This equation is true.
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Yes, the sides form a right triangle.
