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nikitadnepr [17]
3 years ago
8

Plzzz answerrrrrrrrrrr

Mathematics
2 answers:
skelet666 [1.2K]3 years ago
5 0
9. -16
10. 3
11. 4
12. -5
14. -12
15. 20
frutty [35]3 years ago
3 0

Answer:

9. -16

10. 3

11. 4

Step-by-step explanation:

9. 21 = 5 - r

Subtract 5 from both sides;

16 = -r

Divide both sides by -1

-16 = r OR r = -16

10. 8 - 5b = -7

Subtract 8 from both sides;

-5b = -15

Divide both sides by -5

b = 3

11. -10 = 6 - 4m

Subtract 6 from both sides;

-16 = -4m

Divide both sides by -4

4 = m OR m = 4

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Six distinct integers are picked from the set {1, 2, 3,…, 10}. How many selections are there, in which the second smallest integ
Ksivusya [100]

Answer:

1680 ways

Step-by-step explanation:

Total number of integers = 10

Number of integers to be selected = 6

Second smallest integer must be 3. This means the smallest integer can be either 1 or 2. So, there are 2 ways to select the smallest integer and only 1 way to select the second smallest integer.

<u>2 ways</u>   <u>1 way</u>  <u>       </u>  <u>        </u>  <u>        </u>  <u>        </u>

Each of the line represent the digit in the integer.

After selecting the two digits, we have 4 places which can be filled by 7 integers. Number of ways to select 4 digits from 7 will be 7P4 = 840

Therefore, the total number of ways to form 6 distinct integers according to the given criteria will be = 1 x 2 x 840 = 1680 ways

Therefore, there are 1680 ways to pick six distinct integers.

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