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nikitadnepr [17]
3 years ago
8

Plzzz answerrrrrrrrrrr

Mathematics
2 answers:
skelet666 [1.2K]3 years ago
5 0
9. -16
10. 3
11. 4
12. -5
14. -12
15. 20
frutty [35]3 years ago
3 0

Answer:

9. -16

10. 3

11. 4

Step-by-step explanation:

9. 21 = 5 - r

Subtract 5 from both sides;

16 = -r

Divide both sides by -1

-16 = r OR r = -16

10. 8 - 5b = -7

Subtract 8 from both sides;

-5b = -15

Divide both sides by -5

b = 3

11. -10 = 6 - 4m

Subtract 6 from both sides;

-16 = -4m

Divide both sides by -4

4 = m OR m = 4

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nlexa [21]
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The difference between two numbers is 28. The first number is three times the other number. What are the numbers? A. 14 and 42 B
nadezda [96]
The answer would be A. 14 and 42
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Nicolas has $6,500 to deposit into an account which earns 3.25% interest compounded annually. How interest will he have earned a
agasfer [191]

We have been given that Nicolas has $6,500 to deposit into an account which earns 3.25% interest compounded annually. We are asked to find amount of interest earned at the end on 8 years.

We will use compound interest formula to solve our given problem.

A=P(1+\frac{r}{n})^{nt}, where,

A = Final amount,

P = Principal amount,

r = Annual interest rate in decimal form,

n = Number of times interest is compounded per year,

t = Time in years.

3.25\%=\frac{3.25}{100}=0.0325

A=6500(1+\frac{0.0325}{1})^{1\cdot 8}

A=6500(1+0.0325)^{8}

A=6500(1.0325)^{8}

A=6500(1.2915775352963673)

A=8395.253979

Now we will subtract principal amount from final amount to find amount of interest as:

\text{interest}=8395.253979-6500

\text{interest}=1895.253979\approx 1895.25

Therefore, Nicolas would have earned $1895.25 in interest at the end of 8 years.

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What are the roots of f(x)=x2-48
Tcecarenko [31]
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Y=-x^2+6x-4<br> Find the Axis of Symmetry and the Vertex, Also solve the whole equation.
Inessa [10]

Answer:

1. <em>Axis of symmetry</em>: x = 3

2. <em>Vertex:</em> (3,5)

3. <em>Solution of the equation</em>:

<u />

  • x-intercepts:

               (3-\sqrt{5},0) \\\\(3+\sqrt{5},0)

  • y-intercept: (0, -4)

Explanation:

<u>1. Equation:</u>

    y=-x^2+6x-4

<u>2. </u><em><u>Axis of symmetry:</u></em>

That is the equation of a parabola, whose standard form is:

                 y=ax^2+bx+c

Where:    

                 a=-1;b=6;c=-4

The axis of symmetry is the vertical line with equation:

               x=-b/2a

Substitute  a=-1,\text{ and }b=6

          x=-6/[(2)(-1)]=-6/(-2)=3

Thus, the axis of symmetry is:

            x=3

<em><u>3. Vertex</u></em>

<em><u /></em>

The x-coordinate of the vertex is equal to the axys of symmetry, i.e x = 3.

To find the y-xoordinate, substitute this value of x into the equation for y:

               y=-x^2+6x-4\\\\y=-(3)^2+6(3)-4=-9+18-4=5

Therefore, the vertex is (3, 5)

<u>4. Find the x-intercepts</u>

The x-intercepts are the roots of the equation, which are the points wher y = 0.

        y=-x^2+6x-4=0

Use the quadratic equation:

       x=\frac{-b\pm \sqrt{b^2-4ac} }{2a} \\\\x=\frac{-6\pm\sqrt{(-6)^2-4(-1)(-4)} }{2(-1)}\\\\x_1=3-\sqrt{5} \\\\x_2=3+\sqrt{5}

<u>5. Find the y-intercept</u>

<u />

The y-intercet is the value of y when x=0:

         y=-x^2+6x-4\\\\y=-(0)^2+6(0)-4=-4

7 0
4 years ago
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