Answer:
- See attachment for table values
- y₁ = y₂ for x = 6
Step-by-step explanation:
In each case, put the x-value in the formula and do the arithmetic. If you're allowed, you can save some time and effort by realizing that the solution (x) will have to be an even number.
y₁ is an integer value for all integer values of x. y₂ is an integer value for even values of x only. y₁ and y₂ will both be integers (and possibly equal) only when x is even.
For example, for x = 6, we have
... y₁ = 3·6 - 8 = 18 -8 = 10
... y₂ = 0.5·6 +7 = 3 +7 = 10
That is, for x = 6, both columns of the table have the same number (10). That is, y₁ = y₂ for x = 6. The solution to the equation
... y₁ = y₂
is
... x = 6.
The first two negatives cancel out and you're left with positive 4. Now go inside the square root and do the exponent. -4*-4 = 16. Then do the -4*3*1 = -12. Do 16-12 = 4. now the square root of 4 = 2. at the dominator is 2*3 = 6. right now they problem should look like 4+- 2/ 6. from there you split the problem in two. so you have 4+2/6 & 4-2/6 then you solve both problems.
6/6 2/6
1 1/3
1 & 1/3 are your answers. I hope this helped!
Answer:
(1,6) & (7,0)
Step-by-step explanation:
y = -x + 7
y = -0.5(x - 3)² + 8
To solve the system, solve these two equations simultaneously
-x + 7 = -0.5(x - 3)² + 8
-x + 7 = -0.5(x² - 6x + 9) + 8
-x + 7 = -0.5x² + 3x - 4.5 + 8
0.5x² - 4x + 3.5 = 0
x² - 8x + 7 = 0
x² - 7x - x + 7 = 0
x(x - 7) - (x - 7) = 0
(x - 1)(x - 7) = 0
x = 1, 7
y = -1 + 7 = 6
y = -7 + 7 = 0
(1,6) (7,0)
Since the system has two distinct solutions, the line and the curve meet at two distinct poibts9: (1,6) & (7,0)
C. The number of times a dessert was offered at a special price.
