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kirza4 [7]
3 years ago
8

What is the solution to the equation 3x + 2(x - 9) = 8x + X- 14? O-8 -1 O1 O8

Mathematics
2 answers:
anyanavicka [17]3 years ago
8 0
Answer is B -1
Hope it helps
Dovator [93]3 years ago
5 0

Answer:

-1

Step-by-step explanation:

Simplify both sides: 3x + (2(x) + 2(-9)) = 8x + x -14

Add/Combine like terms: 3x+2x= (5x-18) = (9x-14)

New Equation: 5x-18 = 9x-14

add 14 to both sides: 5x-4 = 9x

Subtract 5x from both sides: -4 = 4x

Divide both sides by 4 to get: -1 = x

Answer: x = -1

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Lemur [1.5K]

You must travel at 42 mph for 4 hours

<em><u>Solution:</u></em>

Time varies inversely as rate of motion

Let "t" be the time required

Let "r" be the rate of motion

Then, we get

t \propto \frac{1}{r}\\\\t = k \times \frac{1}{r}\\\\t = \frac{k}{r} -------- eqn 1

Where, "k" is the constant of proportionality

<em><u>You travel 3 hours at a rate of 56 mph</u></em>

Substitute t = 3 and r = 56 in eqn 1

3 = \frac{k}{56}\\\\k = 3 \times 56\\\\k = 168

<em><u>Find the  rate you must travel for 4 hours</u></em>

r = ? and t = 4

Substitute t = 4 and k = 168 in eqn 1

4 = \frac{168}{r}\\\\r = \frac{168}{4}\\\\r = 42

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3 years ago
Pls solve this ,urgent no spam​
aleksklad [387]

Answer:

<u>Question 3</u>

Given expression:

\sf \left(\dfrac{-8}{9} \times \dfrac{1}{-5}\right)+\left(\dfrac{-8}{9} \times \dfrac{-7}{11}\right)

Both parentheses share a common term.

To factor out a common term: ab + ac = a(b + c)

\textsf{Factor out the common term }\dfrac{-8}{9}

\sf \implies\dfrac{-8}{9} \times \left(\dfrac{1}{-5}+\dfrac{-7}{11}\right)

-------------------------------------------------------------------------------------------------

<u>Question 4</u>

To calculate the amount of money Rajni had to begin with, sum the three amounts she spent:

\sf \implies total=10\frac14+25\frac34+16\frac12

As \sf a\frac{b}{c}=a+\frac{b}{c}, then:

\sf \implies 10+\frac14+25+\frac34+16+\frac12

Collect and sum the whole numbers:

\sf \implies (10+25+16)+\frac14+\frac34+\frac12

\sf \implies 51+\frac14+\frac34+\frac12

As  \sf \frac14+\frac34=\frac44=1, then

\sf \implies 51+1+\frac12

\sf \implies 52+\frac12

\sf \implies 52\frac12

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2 years ago
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4 years ago
Todd scored 132 points in 12 games. Terry scored 81 points in 8 games. Which rate is better?
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Jaime has 5 over 11 spaceof a project completed while Tim has finished 7 over 13 spaceof the same project.
faust18 [17]

Answer:

a. Tim has completed a greater amount of work.

b. Together they have completed \frac{142}{143} part of two projects.

Step-by-step explanation:

Let us assume that the project on which Jaime and Tim are working has x amount of space.

Now, given that Jaime has 5 over 11 space of a project completed while Tim has finished 7 over 13 space of the same project.

Therefore, Jaime has completed \frac{5x}{11} amount of space and Tim has finished \frac{7x}{13} amount of space.

a. Now, (7x) \times 11 > (5x) \times 13

⇒ \frac{7x}{13} > \frac{5x}{11}

Therefore, Tim has completed the greater amount of work. (Answer)

b. Together they have completed (\frac{7x}{13} + \frac{5x}{11}) = \frac{(7 \times 11 + 5 \times 13)}{13 \times 11} x = \frac{142}{143}x amount of space out of 2x amount of space. (Answer)

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3 years ago
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