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3 years ago

Kite LMNO is shown below. What is the measure of angle M

Mathematics

1 answer:

goblinko [34]3 years ago

7 0

Answer:

<M = 78°

Step-by-step explanation:

The sum of angles in a kite is 360°.

One of the properties of a kite is that one pair of opposite angles are equal.

Since it is not <L and <N, it must be <O and <M

Therefore:

<O = <M = x

=> x + x + 130 + 74 = 360

2x + 204 = 360

2x = 360 - 204

2x = 156

x = 156/2 = 78°

This means that <M = 78°

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If someone average free throw for basketball is 60% how many times in the next 50 tries will she make a free throw. Describe how

Anon25 [30]

So remember that percent means parts out of 100
60%=60/100=6/10
so every 10 throws she makes 6
how many 5 in 50?
50/10=5
answe ris 5
so 5 tens so therefor 5 sixes
5 times 6=30
answer is 30 throws

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3 years ago

Solving two step equations w/-3+14=5

natali 33 [55]

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⇛ w/–3 = 5 – 14

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2 years ago

Mirror and the three friends each had three over for food of they need it to have 5 feet of rope altogether. Do they have enough

BabaBlast [244]

Answer:

Do they have enough?

Nope, they don't have enough.

Step-by-step explanation:

They would not have enough because 3/4 times 4 would not equal 5...it would equal 3. Mario and his 3 friends each have 3/4 foot of rope. They needed 5 feet of rope altogether. Do they have enough rope? They would need 2 more feet of rope to complete the 5 feet. But they do not have enough feet of rope to make 5 feet.

Hope it helped u if yes mark me BRAINLIEST!

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2 years ago

12.what is the probability that a boy and a girl chosen randsomly will be seniors?

zhenek [66]

$\frac{\textbf{1}}{\textbf{20}}$

Step-by-step explanation:

Probability= $\frac{\text{number of favourable outcomes}}{\text{total number of outcomes}}$

Probability for a randomly chosen girl to be senior= $\frac{\text{number of senior girls}}{\text{total number of girls}}$

Probability for a randomly chosen girl to be senior= $\frac{7}{8+11+9+7}=\frac{7}{35}=\frac{1}{5}$

Probability for a randomly chosen boy to be senior= $\frac{\text{number of senior boys}}{\text{total number of boys}}$

Probability for a randomly chosen girl to be senior= $\frac{9}{10+7+10+9}=\frac{9}{36}=\frac{1}{4}$

For two independent events,

Probability for both event 1 and event 2 to take place= $\text{probability of event 1} \times \text{probability of event 2}$

Since choosing boys and girls is independent,

Probability for both boy an girl chosen to be senior= $\text{probability for boy to be senior}\times\text{probability for girl to be senior}$

Probability for both boy and girl chosen to be senior= $\frac{1}{5} \times \frac{1}{4} = \frac{1}{20}$

So,required probability is $\frac{1}{20}$

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3 years ago

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Answer:

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