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3 years ago

Kite LMNO is shown below. What is the measure of angle M

Mathematics

1 answer:

goblinko [34]3 years ago

7 0

Answer:

<M = 78°

Step-by-step explanation:

The sum of angles in a kite is 360°.

One of the properties of a kite is that one pair of opposite angles are equal.

Since it is not <L and <N, it must be <O and <M

Therefore:

<O = <M = x

=> x + x + 130 + 74 = 360

2x + 204 = 360

2x = 360 - 204

2x = 156

x = 156/2 = 78°

This means that <M = 78°

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Draw a number line diagram and write an expression to represent this situation: “On Tuesday at lunchtime, it was 29^∘C. By sunse

Zinaida [17]

Answer:

not you cheating Maddison (its kaliya)

Step-by-step explanation:

but the answer is the temperature dropped 15.6 degrees from the high that day which was 8 degrees

so the sum is: 8-15.6= -7.6

And that means the low temperature on Tuesday night was - 7.6 degrees

5 0

2 years ago

The percentage of body fat of a random sample of 36 men aged 20 to 29 found a sample mean of 14.42. Find a 95% confidence interv

Rina8888 [55]

Answer:

$14.42-1.96\frac{6.95}{\sqrt{36}}=12.150$

$14.42+ 1.96\frac{6.95}{\sqrt{36}}=16.690$

So on this case the 95% confidence interval would be given by (12.150;16.690)

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X=14.42$ represent the sample mean

$\mu$ population mean (variable of interest)

$\sigma=6.95$ represent the population standard deviation

n=36 represent the sample size

Solution to the problem

The confidence interval for the mean is given by the following formula:

$\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (1)

Since the Confidence is 0.95 or 95%, the value of $\alpha=0.05$ and $\alpha/2 =0.025$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.025,0,1)".And we see that $z_{\alpha/2}=1.96$