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4 years ago

Solve the equation. 8d – 4d – 6d – 8 = 2d

Mathematics

2 answers:

nlexa [21]4 years ago

6 0

Answer:

d=-8

Step-by-step explanation:

8d-4d=4d

4d-6d=-2d

-2d-8=2d

-8=d

d=-8

Ronch [10]4 years ago

4 0

Answer:

d = -4

Step-by-step explanation:

8d-4d-6d-8=2d

-2d - 8 = 2d

-2d = 2d + 8

-4d = 8

d = -4

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One urn contains one blue ball (labeled B1) and three red balls (labeled R1, R2, and R3). A second urn contains two red balls (R

marusya05 [52]

Answer:

(a) See attachment for tree diagram

(b) 24 possible outcomes

Step-by-step explanation:

Given

$Urn\ 1 = \{B_1, R_1, R_2, R_3\}$

$Urn\ 2 = \{R_4, R_5, B_2, B_3\}$

Solving (a): A possibility tree

If urn 1 is selected, the following selection exists:

$B_1 \to [R_1, R_2, R_3]; R_1 \to [B_1, R_2, R_3]; R_2 \to [B_1, R_1, R_3]; R_3 \to [B_1, R_1, R_2]$

If urn 2 is selected, the following selection exists:

$B_2 \to [B_3, R_4, R_5]; B_3 \to [B_2, R_4, R_5]; R_4 \to [B_2, B_3, R_5]; R_5 \to [B_2, B_3, R_4]$

See attachment for possibility tree

Solving (b): The total number of outcome

For urn 1

There are 4 balls in urn 1

$n = \{B_1,R_1,R_2,R_3\}$

Each of the balls has 3 subsets. i.e.

$B_1 \to [R_1, R_2, R_3]; R_1 \to [B_1, R_2, R_3]; R_2 \to [B_1, R_1, R_3]; R_3 \to [B_1, R_1, R_2]$

So, the selection is:

$Urn\ 1 = 4 * 3$

$Urn\ 1 = 12$

For urn 2

There are 4 balls in urn 2

$n = \{B_2,B_3,R_4,R_5\}$

Each of the balls has 3 subsets. i.e.

$B_2 \to [B_3, R_4, R_5]; B_3 \to [B_2, R_4, R_5]; R_4 \to [B_2, B_3, R_5]; R_5 \to [B_2, B_3, R_4]$

So, the selection is:

$Urn\ 2 = 4 * 3$

$Urn\ 2 = 12$

Total number of outcomes is:

$Total = Urn\ 1 + Urn\ 2$

$Total = 12 + 12$

$Total = 24$

5 0

3 years ago

You would like to buy new carpet for a room. The room is rectangular. The dimensions are 12 1 third feet by 10 3 over 4 feet. Ho

KatRina [158]

12 1/3 * 10 3/4 = 132.583ft^2
= 133ft^2

3 0

3 years ago

HEY PLEASE HELP I AM STRUGGLING!!

Maksim231197 [3]

Answer:

Step-by-step explanation:

ok the first box is linear

the 2nd isnt

the 3rd isnt either

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8 0

3 years ago

It's in the attachment URGENT

maxonik [38]

Step-by-step explanation:

$\frac{2a}{a + b - c} = \frac{2b}{b + c - a} = \frac{2c}{a + c - b} = k \\ \\ by \: theorem \: on \: equal \: ratios \\ \\ \frac{2a + 2b + 2c}{a + b - c + b + c - a + a + c - b} = k \\ \\ \frac{2(a + b + c)}{a + b + c} = k \\ \\ \therefore \: k = 2$

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3 years ago

Simplify. (fg2)4 Can you please help me? I'm stuck on this question

Natasha2012 [34]

Answer:

$4fg^{2}$

Step-by-step explanation:

1) Remove parentheses.

$fg^{2} *4$

2) Regroup terms.

$4fg^{2}$

5 0

3 years ago