X^2 = 24^2 + 7^2
x^2 = 576 + 49
x^2 = 625
x = 25
There is a formula which employs the use of determinants and which helps us calculate the area of a triangle if the vertices are given as
. The formula is as shown below:
Area=
Now, in our case, we have: 
, and

Thus, the area in this case will become:
Area=
Therefore, Area=![\frac{1}{2}\times [[3(-1\times 1-(-5)\times 1]-3[3\times 1-(-2)\times 1]+1[3\times -5-2]]= \frac{1}{2}\times -20=-10](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%5Ctimes%20%5B%5B3%28-1%5Ctimes%201-%28-5%29%5Ctimes%201%5D-3%5B3%5Ctimes%201-%28-2%29%5Ctimes%201%5D%2B1%5B3%5Ctimes%20-5-2%5D%5D%3D%20%5Cfrac%7B1%7D%7B2%7D%5Ctimes%20-20%3D-10)
We know that area cannot be negative, so the area of the given triangle is <u>10 squared units</u>.
Answer:

Step-by-step explanation:
Given



Required
The solution
Differentiate

Next, we solve for c1 and c2
implies that; x = 1 and y = 0
So, we have:

--- (1)
implies that: x = 1 and y' = e
So, we have:


--- (2)
Add (1) and (2)


Divide both sided by e

Divide both sides by 2

Substitute
in 

Rewrite as:

Multiply both sides by e

So, we have:



Answer:
-10 7/20
Step-by-step explanation:
Brainliest maybe???