All categories

3 years ago

Please Solve Fast MUST EXPLAIN EVERYTHING

Mathematics

2 answers:

Sonja [21]3 years ago

3 0

Answer:

I can barely see the image can you make another one and zoom in on the image? Thanks for your support! Have a nice day!

Law Incorporation [45]3 years ago

3 0

Irdk did y’all find the answer

You might be interested in

35% of students take spainsh or engineering. 30% of students take Spanish. 25% of students take engineering. What is the probabi

vladimir2022 [97]

Answer:

0.2 = 20% probability that a student takes Spanish and engineering

Step-by-step explanation:

We solve this question treating the probabilities as Venn sets.

I am going to say that:

Event A: Student takes Spanish

Event B: Student takes Engineering.

35% of students take spainsh or engineering.

This means that $P(A \cup B) = 0.35$

30% of students take Spanish.

This means that $P(A) = 0.3$

25% of students take engineering.

This means that $P(B) = 0.25$

What is the probability that a student takes Spanish and engineering?

This is $P(A \cap B)$ .

These probabilities are related by the following formula:

$P(A \cup B) = P(A) + P(B) - P(A \cap B)$

$P(A \cap B) = P(A) + P(B) - P(A \cup B)$

Replacing the values

$P(A \cap B) = 0.3 + 0.25 - 0.35 = 0.2$

0.2 = 20% probability that a student takes Spanish and engineering

7 0

3 years ago

A 4-foot-long sandwich is cut into servings that are each foot long. How many servings will there be after the sandwich is cut?

NeX [460]

Answer: 12

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

A small airplane is approaching a stationary crowd at 100 meters per second. The engine of the plane is emitting a sound of 485

jeka57 [31]

Answer:

695.87 Hz

Step-by-step explanation:

Using the equation for Doppler shift, the frequency of the apparent sound is f' = f(v ± v')/(v ± v") where f = frequency of sound emitted by the plane's engine = 485 Hz, v = speed of sound in air = 330 m/s, v' = speed of crowd(detector) = 0 m/s (since the crowd are stationary) and v" = speed of plane(source) = 100 m/s

So, f' = f(v ± v')/(v ± v")

f' = f(v ± 0)/(v ± v")

f' = fv/(v ± v")

Since the source moves towards the detector, we use a minus a minus sign in the denominator to get a shift upwards in frequency since a shift upwards means the objects are moving closer to each other.

So,

f' = fv/(v - v")

Substituting the values of the variables into the equation, we have

f' = 485 Hz × 330 m/s/(330 m/s - 100 m/s)

f' = 160050 Hzm/s ÷ 230 m/s

f' = 695.87 Hz

5 0

3 years ago

Please answer this with explanation. Please I really am struggling. I will mark you brainalist. Please solve it Please

Hatshy [7]

Answer:

13, 11, 4, 16, 6, 22