Answer:
x = 4 and y = 1
Step-by-step explanation:
The given equations are :
2x+5y = 13 ...(1)
3x-2y = 10 ...(2)
The elimination method is appropriate to solve the given system of equations.
Multiply equation (1) by 3 and equation (2) by 2.
6x+15y=39 ...(3)
6x-4y=20 ...(4)
Subtract equation (3) from (4).
6x-4y-(6x+15y) = 20-39
6x-4y-6x-15y = -19
-19y=-19
y = 1
Put the value of y in equation (1).
2x+5y = 13
2x+5=13
2x=8
x = 4
So, the solution of the given equations are x = 4 and y = 1.
