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Keith_Richards [23]

3 years ago

9

How do you add integers with different signs?

1 answer:

Svet_ta [14]3 years ago

3 0

Answer:

To add integers with different signs, keep the sign of the number with the largest absolute value and subtract the smallest absolute value from the largest.

Step-by-step explanation:

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Ashley is going to rent a truck for one day. There are two companies she can choose from, and they have the following prices.

Kay [80]

Answer:

Anything above 15 miles, so x>15

Step-by-step explanation:

When you solve this by using an equation, you would get 77=65+0.80m (0.80 m because slope is 0.80 and m is mileage you multiply by). You would subtract 64 from both sides, so 12=0.80m and then you divide 0.80 by 12 to get m by itself to get 15. 15 miles is when both companies cost the same, so anything above 15.

3 0

4 years ago

State whether the slope of the line is positive, negative, zero or undefined.

Shkiper50 [21]

That flat horizontal line has zero slope. There's no change in y for every unit change in x.

7 0

4 years ago

Read 2 more answers

Can someone please help me with this similar area question? I have the answer but I’m not sure how to get to it. Will make brain

Mumz [18]

Step-by-step explanation:

well there is a very simple point that you have mistaken tho:

484cm², 25cm²

Areas are defined in square cm but the radius is in cm

so:

$\sqrt{ \frac{484 {cm}^{2} }{25 {cm}^{2} } } = \frac{7.92}{r} = = = > 4.4 = \frac{7.92cm}{x} = = > x = \frac{7.92cm}{4.4} = x = 1.8cm$

and there you go

5 0

2 years ago

Call an integer $n$ oddly powerful if there exist positive integers $a$ and $b$, where $b>1$, $b$ is odd, and $a^b = n$. How

azamat

Answer:

There are 16 oddly powerful integers less than 2010

Step-by-step explanation:

∵ b is an odd integer

∵ b > 1

∴ The first value of b is 3

∵ a is an integer

- We can use a = 1, 2, 3, ..........

∵ $a^{b}=n$

∵ n < 2010

- Let a = 1, 2, ............... 12 because 12³ is greatest integer < 2010

∵ 1³ = 1, 2³ = 8, 3³ = 27, 4³ = 64, 5³ = 125, 6³ = 216, 7³ = 343,

8³ = 512, 9³ = 729, 10³ = 1000, 11³ = 1331, 12³ = 1728

∴ There are 12 oddly powerful integers with b = 3

Now the second value of b is 5

$1^{5}=1$ but we took 1 before so we will start with 2

∵ $2^{5}=32$ , $3^{5}=243$ , $4^{5}=1024$

- $4^{5}$ is the greatest integer < 2010

∴ There are 3 oddly powerful integers with b = 5

Now the third value of b is 7

∵ $2^{7}=128$

- $2^{7}$ is the greatest integer < 2010

∴ There is 1 oddly powerful integers with b = 7

Now the fourth value of b is 9

∵ $2^{9}=512$

- $2^{9}$ is the greatest integer < 2010

- But we used 512 before

∴ There is no oddly powerful integers with b = 9

- 9 is the greatest value of b which makes $a^{b}$

∵ 12 + 3 + 1 = 16

∴ There are 16 oddly powerful integers less than 2010

5 0

3 years ago

What is the minimum point of the graph???

Natasha2012 [34]

Answer:

(-2,1)

Step-by-step explanation:

Since this is an upwards opening parabola, the minimum point is at the vertex

We can find the x coordinate of the vertex by

y = 2x^2 +8x +9

where a=2 b =8 and c =9

x = -b/2a

x = -8/(2*2)

= -8/4 = -2

The x coordinate is -2

Now substitute this in to find the y coordinate

y = 2(-2)^2 +8(-2)+9

= 2*4 -16+9

8-16+9

=1

The vertex = (-2,1), which is the minimum point

8 0

4 years ago

Read 2 more answers