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alisha [4.7K]
2 years ago
7

Explain how you would create opposite terms for the x-variable in this system.

Mathematics
1 answer:
Ray Of Light [21]2 years ago
7 0

Answer:

Your answer would be, You can use the Elimination Method, by Multiplying, One or Both Equations by a Constant.

Solve System of Linear Equation:

3x - 6y = -8, -1/4x + 4y = 6 ====> y = 32 /21; x = 8 / 21

Steps:

[ 3x - 6y = -8, -1 / 4x + 4y = 6 ]

Isolate x for 3x - 6y = -8: x = -8 + 6y / 3

3x - 6y = -8

Add 6y both sides:

3x - 6y + 6y = -8 + 6y

Simplify:

3x = - 8 + 6y

Divide Both sides by 3:

3x / x = -8 / 3 + 6y / 3

Simplify:

x = -8 + 6y / 3

Substitute:

x = -8 + 6y / 3

[ 1 / 4 * -8 + 6y / 3 + 4y = 6 ]

Isolate:

-1 / 4 -8 + 6y / 3 + 4y = 6

y = 32 / 21

For x = -8 + 6y / 3

Substitute:

y = 32 / 21

x = -8 + 6 / 3 * 32 / 21

-8 + 6 / 3 * 32 / 21

x = 8 / 21

The Solution to the Systems of Equations are: y = 32 / 21; x = 8 / 21

Hope that helps!!! : )

Step-by-step explanation:

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Find y when x=77, if y varies inversly as x, and y = 23 when x = 115.
Eduardwww [97]

The required value of y is 2645 / 77 when x = 77.

Step-by-step explanation:

1. Let's check the information given to answer:

if y varies inversely as x, and y = 23 when x = 115. Find y when x=77

2. What is y when x = 77?

As the statement "y varies inversely as x" translates into y = k/x

If we let y = 23 and x = 115, the constant of variation becomes

        23 = k ÷ 115

        k = 23 × 115

        k = 2645

Thus the specification equation is y = 2645  ÷ x . Now, letting x = 77, we obtain

          y = 2645 ÷ x

          y = 2645 ÷ 77

<u>So, The required value of y = 2645 / 77 when x = 77</u>

<u></u>

<u>#learnwithBrainly</u>

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