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SOVA2 [1]
2 years ago
8

What is the distance between (-3, 2) and (2, -1)

Mathematics
2 answers:
MariettaO [177]2 years ago
6 0

Answer:

(5,-3)

Step-by-step explanation:

Katena32 [7]2 years ago
6 0

Step-by-step explanation:

(-3,2)=(x1,y1)

(2,-1)=(x2,y2)

distance(d)^2=(x2-x1)^2+(y2-y1)^2

d^2 =(2+3)^2+(-1-2)^2

d^2 =25+9

d^2=34

d=√34

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mart [117]
This question can be solved using the Herons equation where 
A = SQRT [s*(s-a)*(s-b)*(s-c)]

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s = (a+b+c)/2

Since we are given the area, we can express "s" as a function of the third side c. This can be substituted in the original equation so as to obtain an expression to solve for the third side c

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3 years ago
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VMariaS [17]
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6 0
2 years ago
Dos cuadrados de lado
Kaylis [27]

La franja amarilla del rectángulo tiene un área de 30 centímetros cuadrados.

<h3>¿Cuál es el área de la franja amarilla del rectángulo?</h3>

En este problema tenemos un rectángulo formado por dos cuadrados que se traslapan uno al otro. La franja amarilla es el área en la que los cuadrados se traslapan. La anchura del rectángulo es descrita por la siguiente ecuación:

(10 - x) + 2 · x = 17

Donde x se mide en centímetros.

A continuación, despejamos x en la ecuación descrita:

10 + x = 17

x = 7

Ahora, el área de la franja amarilla se determina mediante la fórmula de area de un rectángulo:

A = b · h

Donde:

  • b - Base del rectángulo, en centímetros.
  • h - Altura del rectángulo, en centímetros.
  • A - Área del rectángulo, en centímetros cuadrados.

A = (10 - 7) · 10

A = 3 · 10

A = 30

El área de la franja amarilla del rectángulo es igual a 30 centímetros cuadrados.

Para aprender más sobre áreas de rectángulos: brainly.com/question/23058403

#SPJ1

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Answer:

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Step-by-step explanation:

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