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mina [271]
3 years ago
9

A non- zero number raised to the zero exponent equals

Mathematics
2 answers:
leonid [27]3 years ago
8 0
Always one. 0/0 is indeterminate
Serjik [45]3 years ago
6 0
The correct answer is 1
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Do you know how to do it on your calculator?
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. QUIZ You answered 14 questions correctly on a 15-question quiz. What percent did you receive on the quiz? Round to the nearest
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Step-by-step explanation:

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frosja888 [35]
The solution of the system can be x - 3y = 4 only if both the equations can be simplified to x - 3y = 4.

This will mean that both the equations will result in the same line which is x - 3y = 4 and thus have infinitely many solutions.

Second equation is:

Qx - 6y = 8 
Taking 2 common we get:

(Q/2)x - 3y = 4

Comparing this equation to x- 3y = 4, we can say that 

Q/2 = 1
So,
Q = 2

Therefore, the second equation will be:

2x - 6y = 8
5 0
3 years ago
Let x be a Poisson random variable with μ = 9.5. Find the probabilities for x using the Poisson formula. (Round your answers to
miv72 [106K]

Answer: 1

Step-by-step explanation: the probability mass function that defines a possion probability distribution is given below as

P(x=r) = e^-u × u^x/x!

For this question, x = 0 and u = 9.5

Hence we have that

P(x=0) = e^-0 × 9.5^0 / 0!

P(x=0) = 1 × 1/ 1 = 1

5 0
3 years ago
A vector with magnitude 9 points in a direction 190 degrees counterclockwise from the positive x axis. Write in component form
Over [174]

Answer:

\vec{v}= \text{ or } \approx

Step-by-step explanation:

Component form of a vector is given by \vec{v}=, where i represents change in x-value and j represents change in y-value. The magnitude of a vector is correlated the Pythagorean Theorem. For vector \vec{v}=, the magnitude is ||v||=\sqrt{i^2+j^2.

190 degrees counterclockwise from the positive x-axis is 10 degrees below the negative x-axis. We can then draw a right triangle 10 degrees below the horizontal with one leg being i, one leg being j, and the hypotenuse of the triangle being the magnitude of the vector, which is given as 9.

In any right triangle, the sine/sin of an angle is equal to its opposite side divided by the hypotenuse, or longest side, of the triangle.

Therefore, we have:

\sin 10^{\circ}=\frac{j}{9},\\j=9\sin 10^{\circ}

To find the other leg, i, we can also use basic trigonometry for a right triangle. In right triangles only, the cosine/cos of an angle is equal to its adjacent side divided by the hypotenuse of the triangle. We get:

\cos 10^{\circ}=\frac{i}{9},\\i=9\cos 10^{\circ}

Verify that (9\sin 10^{\circ})^2+(9\cos 10^{\circ})^2=9^2\:\checkmark

Therefore, the component form of this vector is \vec{v}=\boxed{}\approx \boxed{}

6 0
3 years ago
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