He paid $30 so that's would be constant. $4 each ride so that would be slope:
So equation would be y = 4x + 30
So answer is D.
Answer:
The 99% confidence interval for the mean loss in value per home is between $5359 and $13463
Step-by-step explanation:
We are in posession of the sample's standard deviation, so we use the student's t-distribution to solve this question.
The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So
df = 45 - 1 = 44
99% confidence interval
Now, we have to find a value of T, which is found looking at the t table, with 44 degrees of freedom(y-axis) and a confidence level of
). So we have T = 2.6923
The margin of error is:
M = T*s = 1505*2.6923 = 4052.
In which s is the standard deviation of the sample.
The lower end of the interval is the sample mean subtracted by M. So it is 9411 - 4052 = $5359
The upper end of the interval is the sample mean added to M. So it is 9411 + 4052 = $13463
The 99% confidence interval for the mean loss in value per home is between $5359 and $13463
Answer:
Before discount = $61.25
After discount = $49.00
Step-by-step explanation:
Given information:
- Discount = $12.25
- Coupon = 20%
The price of the gift before the discount is 100%.
If the $12.25 discount was 20% of the purchase price, then:
⇒ original price (before discount) = (12.25 / 20) × 100 = $61.25
To find the price after the discount, simply subtract the discount from the found original price:
⇒ $61.25 - $12.25 = $49.00
<u>Conclusion</u>
- Before discount price = $61.25
- After discount price = $49.00
answer:
90 degrees + 28 degrees= 118 degrees
180-118= Z is 62 degrees
13y-1 = 24 2x-7 = 39
+1 +1 +7 +7
13y = 25 2x = 46
/13 /13 /2 /2
y = 1.92 X = 23