The answer would be A. When using Cramer's Rule to solve a system of equations, if the determinant of the coefficient matrix equals zero and neither numerator determinant is zero, then the system has infinite solutions. It would be hard finding this answer when we use the Cramer's Rule so instead we use the Gauss Elimination. Considering the equations:
x + y = 3 and <span>2x + 2y = 6
Determinant of the equations are </span>
<span>| 1 1 | </span>
<span>| 2 2 | = 0
</span>
the numerator determinants would be
<span>| 3 1 | . .| 1 3 | </span>
<span>| 6 2 | = | 2 6 | = 0.
Executing Gauss Elimination, any two numbers, whose sum is 3, would satisfy the given system. F</span>or instance (3, 0), <span>(2, 1) and (4, -1). Therefore, it would have infinitely many solutions. </span>
Answer:
Step-by-step explanation:
V of a cube is s^3
V = 512
s = cube root of (V)
s = cube root of 512 cm^3
s = 8
The area of one face of the cube is s^2
s = 8
Area 1 face = 8^2
Area of 1 face = 64 cm^2

Step-by-step explanation:
find the value of the constant of proportionality k

c =total cost
d =days
Answer:
We would have

where " l " is length, " w" is width and "h" is height.
Step-by-step explanation:
Step 1
Remember that
Surface area for a box with no top = 
where " l " is length, " w" is width and "h" is height.
Step 2.
Remember as well that
Volume of the box = 
Step 3
We can now use lagrange multipliers. Lets say,

and

By the lagrange multipliers method we know that

Step 4
Remember that

and

So basically you will have the system of equations

Now, remember that you can multiply the first eqation, by "l" the second equation by "w" and the third one by "h" and you would get

Then you would get

You can get rid of
from these equations and you would get

And from those equations you would get

Now remember the original equation

If we plug in what we just got, we would have

Answer:
-3x + 8
Step-by-step explanation:
Simplify. combine like terms (terms with the same amount of variables).
Subtract -2x and x: -2x - x = -3x
-3x + 8 is your answer.
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